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python - Visual Studio,Marmalde C++ : import libpython. a,在 arm 上的嵌入式解释器中运行 python 代码

转载 作者:太空宇宙 更新时间:2023-11-04 13:50:34 32 4
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我正在尝试在 arm 设备的嵌入式解释器中运行 python 代码;使用 marmalade studio 在 vi​​sual studio 2012 中构建。

我已经构建了我的存档静态链接库,libpython.a,并放在\lib\arm\libpython.a(和 libpython_d.a)下

我已经为 ARM 编译了 python 库,在“libpython.a”中加载似乎工作正常,当我指定错误的外部函数参数数据类型时,“VS:intellisense”给了我错误。 (这是一件好事,意味着至少连接了一些东西)

我的果酱 .mkb 构建文件如下所示:

files
{
RunPython.cpp
}

subprojects
{
}
librarys
{
<arm_shared>
"./lib,libpython"
}

运行Python.cpp

extern void PyRun_SimpleString(const char*);
extern void Py_Initialize(void);
extern void Py_Finalize(void);


const char *pycode=
"print('This is python code')\n";

// Main entry point for the application
int main()
{

//python shared library test

Py_Initialize();
PyRun_SimpleString(pycode);
Py_Finalize();

return 0;
}

问题:我有哪些选择?错误 MSB6006:“link.exe”退出,代码为 1。

我关闭了整个程序优化


更新:

我已经在安装了 visual studio 2012 express 和 marmalade 7.2 的全新 windows-7 64 位安装上重新安装了我的开发环境。

我已经在我的项目文件中添加了适当的链接;仍然收到:错误 MSB6006:“link.exe”退出,代码为 1。

我决定使用 processmonitor:process tree 进行调查,以查看它在运行时访问的目录(记住我需要的库位于名为“libpython”的文件夹中:

arm-none-eaabi-g++.exe
command:
"c:/marmalade/7.2/s3e/gcc/win32/bin/arm-none-eabi-g++.exe" "@arm-none-eabi-g++_cmd_line_MainThread.txt"

childprocess:
collect2.exe
command:
"c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/collect2.exe" "--sysroot=c:\marmalade\7.2\s3e\gcc\win32\bin\../arm-none-eabi" "-X" "-pie" "-o" "Debug_RunPython_vc11x_gcc_arm/RunPython.elf" "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/crti.o" "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/crtbegin.o" "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/../../../../arm-none-eabi/lib/crt0.o" "-Lc:/marmalade/7.2/s3e/lib/arm" "-Lc:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4" "-Lc:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc" "-Lc:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/../../../../arm-none-eabi/lib" "-Lc:/marmalade/7.2/s3e/gcc/win32/bin/../arm-none-eabi/lib" "@C:\Users\root\AppData\Local\Temp\cc8DfmXx" "--start-group" "-lgcc" "-lc" "--end-group" "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/crtend.o" "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/crtn.o"

childprocess:
ld.exe
command: "c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/../../../../arm-none-eabi/bin/ld.exe" "@C:\Users\root\AppData\Local\Temp\cce3XLB7"

关于为什么链接器甚至在目录中查找的任何想法?一定是我做错了什么,或者这是果酱特有的问题我将尝试将我的库放入它确实查找的文件夹中,看看是否可行

另一件令人费解的事情是参数 -l 和 python 之间没有空格

1> c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/../../../../arm -none-eabi/bin/ld.exe: 找不到 -lC:/Marmalade/7.2/s3e/lib/arm/python_d.a


编辑:Error 1 error : ld returned 1 exit status collect2.exe 是链接器问题<​​/p>

1> Build started: Project: RunPython_vc11x, Configuration: GCC ARM Debug Win32 
1> ARM Compiling(GCC) c:\python_compile\RunPython.cpp ...
1> ARM Linking(GCC) ...
1> c:/marmalade/7.2/s3e/gcc/win32/bin/../lib/gcc/arm-none-eabi/4.7.4/../../../../arm-none-eabi/bin/ld.exe: cannot find -llibpython_d
1>collect2.exe : error : ld returned 1 exit status
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

我通过在属性下添加我的库目录来解决它(使用/而不是\,有点反直觉):

C/C++ >general> 附加包含目录:使用 c:/.../lib/arm(不是 C:...\lib\arm)Linker>general> Additional include directories : using c:/.../lib/arm (不是 C:...\lib\arm)链接器>输入>附加依赖项:libpython_d.a


编辑:我之前在 visual studio 说“函数太多参数”时遇到了麻烦但我发现这只是回到 python 头文件以将我的 extern 数据类型与库函数数据类型相匹配的问题。

C++ extern function error: too many arguments to function

最佳答案

想通了,marmalade 中间件,在链接时添加“lib”和附加“_d.a”。所以只需引用“库”ex,lib“library”_d.a

MKB:

    files
{
RunPython.cpp
}


librarys
{
<arm_shared>
"../python-master,python"
}
includepaths
{

../pythonMaster/
../pythonMaster/upstream/Python
../pythonMaster/upstream/Include
}

ROOTFOLDER
+-- lib
+-- arm
| +-- libBASENAME.a
| +-- libBASENAME_d.a
| +-- v5
| +-- libBASENAME.a
| +-- v6
| +-- libBASENAME.a
| +-- vfp
| |-- libBASENAME.a
+-- x86
+-- libBASENAME.lib
+-- libBASENAME_d.lib
+-- darwin
+-- libBASENAME.lib
+-- libBASENAME_d.lib

关于python - Visual Studio,Marmalde C++ : import libpython. a,在 arm 上的嵌入式解释器中运行 python 代码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23572592/

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