c++ - 在 C++ 中切换到循环

Question

我正在尝试完成我的 C++ 类(class)的作业，但我真的卡住了。我不确定我是否正确地解决了这个问题。我正在尝试制作一个基于菜单的程序，它将根据用户的菜单选择将项目添加到“购物车”，并允许用户增加他们的“购物车”中的门票数量。

然后，如果他们按 N，它将返回到主菜单，只有当他们按 5“结帐”时，它才会显示他们的订单总额。

非常感谢任何帮助。

谢谢

#include <iostream>

using namespace std;

int main()
{
    char menuOpt;
    int total = 0;
    char moreTix;

    cout << "Use menu options 1-5 to add a ticket to your cart." << endl;
    cout << "Option 1: Adult - Airboat ride & alligator wrestling show.\n";
                       cout << "\t  Price: $10" << endl;
    cout << "Option 2: Adult - Airboat ride, alligator wrestling show & photo with wrestler.\n";
                       cout << "\t  Price: $15" << endl;
    cout << "Option 3: Senior - Airboat ride & alligator wrestling show.\n";
                       cout << "\t  Price: $7" << endl;
    cout << "Option 4: Child - Airboat ride, alligator wrestling show & stuffed toy alligator.\n";
                       cout << "\t  Price: $10" << endl;
    cout << "Option 5: Checkout"
    cout << "Option: ";
        cin >> menuOpt;

    do{
        switch(menuOpt){
        case '1': cout << "Adult airboat ride & alligator wrestling show has been added to your cart." << endl;
                    total += 10;
                    break;
        case '2': cout << "Adult airboat ride, alligator wrestling show & photo with wrestler has been added to your cart." << endl;
                    total += 15;
                    break;
        case '3': cout << "Senior airboat ride & alligator wrestling show has been added to your cart." << endl;
                    total += 7;
                    break;
        case '4': cout << "Child airboat ride, alligator wrestling show & stuffed toy alligator has been added to your cart." << endl;
                    total +=10;
                    break;
        case '5': cout << "The total for your purchase is $" << total << endl;
        default: cout << "You have made an invalid choice. Please make another selection." << endl;
        }
        cout << "Would you like to purchase another ticket? (Y/N) ";
            cin >> moreTix;
    }while (moreTix == 'y' || moreTix == 'Y');

    return 0;
}

Answer 1

如果我对您的问题的理解正确，一旦用户选择购买更多门票，您将无法看到菜单。

将你的 do 语句放在这一行之上，它应该可以工作:

cout << "Use menu options 1-5 to add a ticket to your cart." << endl;