java - 当我尝试在 hibernate 中创建两个主键时，我陷入困境

Question

我的出勤率是这样的

public class Attendance  implements Serializable
{
    private Integer id,userId;
    private Date date;
    private  OfficeTime officeTime;
    private Set<TimeSlice> timeSlices;
    public Attendance()
    {

    }
}

现在我尝试使用hibernate映射composite-id创建两个主键

 <hibernate-mapping>
          <class name="Attendance">
           <composite-id>
              <key-property name="id"><generator class="increment"/></key-property>
              <key-property name="date" />
          </composite-id>

          <property name="userId" />

          <set name="timeSlices" cascade="all" >
            <key column="attendanceId" />
            <one-to-many class="TimeSlice" />
          </set>

          <many-to-one name="officeTime" class="OfficeTime"
            column="office_id" unique="true" not-null="true"
            cascade="all" />

          </class>

          </hibernate-mapping>

当我这样做时，我收到错误元素类型“key-property”的内容必须匹配“(meta*,column*,type?)”。如何设置两个主键，其中一个必须自动递增。先谢谢了。

Answer 1

您当前的配置不遵循为composite-id 元素设置的架构。以下是复合 id 的架构文档:

<composite-id name="propertyName" class="ClassName" mapped="true|false" access="field|property|ClassName"> node="element-name|." <key-property name="propertyName" type="typename" column="column_name"/> <key-many-to-one name="propertyName class="ClassName" column="column_name"/> ...... </composite-id>

这是一个示例配置:

<composite-id>
            <key-many-to-one name="username" class="org.myclass.UserDB" column="user_name"/>
            <key-property name="role" type="string" column="role_name"/>
        </composite-id>      

相关文档位于:https://docs.jboss.org/hibernate/orm/3.3/reference/en/html/mapping.html#mapping-declaration-compositeid