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c++ - 层序遍历 : Deleting a Subtree

转载 作者:太空宇宙 更新时间:2023-11-04 13:36:11 25 4
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#include <iostream>

using namespace std;

struct node {
int item;
node* l;
node* r;
node (int x) {
item = x;
l = 0;
r = 0;
}
node(int x, node* l, node* r) {
item = x;
this->l = l;
this->r = r;
}
};

typedef node* link;

class QUEUE {
private:
link* q;
int N;
int head;
int tail;
public:
QUEUE(int maxN) {
q = new link[maxN + 1];
N = maxN + 1;
head = N;
tail = 0;
}
int empty() const {
return head % N == tail;
}
void put(link item) {
q[tail++] = item;
tail = tail % N;
}

link get() {
head = head % N;
return q[head++];
}
};

link head = 0; // Initial head of the tree

link find(int x) {
if (head == 0) {
cout << "\nEmpty Tree\n";
return 0;
}
link temp = head;
// To find the node with the value x and return its link
QUEUE q(100);
q.put(temp);
while (!q.empty()) {
temp = q.get();
if (temp->item == x) {
return temp;
}
if (temp->l != 0) q.put(temp->l);
if (temp->r != 0) q.put(temp->r);
}
return 0;
}

void print(link temp) {
QUEUE q(100);
q.put(temp);
while (!q.empty()) {
temp = q.get();
cout << temp->item << ", ";
if (temp->l != 0) q.put(temp->l);
if (temp->r != 0) q.put(temp->r);
}
}

void deleteAll(link h) {
// This deletes the entire binary tree
QUEUE q(100);
q.put(h);
while (!q.empty()) {
h = q.get();
if (h->l != 0) q.put(h->l);
if (h->r != 0) q.put(h->r);
delete h;
}
}

int main() {
link temp = 0;
char c;
int n1, n2;
cout << "\n\nPlease enter the input instructions (X to exit program) : \n\n";
do {
cin >> c;
switch (c) {
case 'C': cin >> n1;
if (head == 0) {
head = new node(n1);
cout << "\nRoot node with item " << n1 << " has been created\n\n";
} else {
cout << "\nError: Tree is not empty\n\n";
}
break;

case 'L': cin >> n1 >> n2;
temp = find(n1);
if (temp != 0) {
if (temp->l == 0) {
temp->l = new node(n2);
cout << "\nNode with item " << n2 << " has been added\n\n";
}
else {
cout << "\nError: The specified node already has a left child\n\n";
}
}
else {
cout << "\nError: The specified node doesn't exist\n\n";
}
break;

case 'R': cin >> n1 >> n2;
temp = find(n1);
if (temp != 0) {
if (temp->r == 0) {
temp->r = new node(n2);
cout << "\nNode with item " << n2 << " has been added\n\n";
}
else {
cout << "\nError: The specified node already has a right child\n\n";
}
}
else {
cout << "\nError: The specified node doesn't exist\n\n";
}
break;

case 'P': cin >> n1;
temp = find(n1);
if (head != 0) {
cout << "\nLevel-order traversal of the entire tree: ";
print(temp);
}
else {
cout << "\nError: No elements to print\n\n";
}
break;

case 'D': cin >> n1;
temp = find(n1);
deleteAll(temp);
temp = 0;
break;

case 'X': cout << "\nExiting Program\n\n";
break;

default: cout << "\nInvalid input entered. Try again.\n\n";

}
} while (c != 'X');
system("pause");
return 0;
}

示例输入:

C 9
L 9 8
R 9 6
L 8 3
R 8 5
R 6 2
L 3 4
L 4 10
L 5 1
R 5 11
L 1 12
R 1 7

一切正常,直到我删除一个子树并在崩溃前打印垃圾值时打印。请帮助我找出错误,因为我已经尝试了几个小时但没有成功。

一切正常,直到我删除一个子树并在崩溃前打印垃圾值时打印。请帮助我找出错误,因为我已经尝试了几个小时但没有成功。

最佳答案

尝试递归函数:

void Delete(link h)
{
if(h)
{
if(h->l) Delete(h->l);
if(h->r) Delete(h->r);
delete(h);
}
}

关于c++ - 层序遍历 : Deleting a Subtree,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29484721/

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