c++ - 如何在 C++ 中将字符串时间转换为无符号整数

Question

我需要将 string 时间转换为 unsigned int 我用 atoi/strtoul/atol 和 string stream< 测试我的程序 但它们无法正常工作，我错过了什么？？？

 string CurrentTime(){
        time_t rawtime;
        struct tm * timeinfo;
        char bffr [80];

        time (&rawtime);
        timeinfo = localtime (&rawtime);

        strftime (bffr,80,"%T",timeinfo);
        // puts (bffr);

        return bffr;
    }

    int main(){
    string new_time;
    new_time = CurrentTime();
    stringstream strValue;
        strValue << new_time;
    unsigned int stime;
        strValue >> stime;
    cout<<stime<<endl;
    cout<<new_time<<endl;
    }

和

 int main(){
        string new_time;
        new_time = CurrentTime();
unsigned int stime =atoi(new_time.c_str());
cout<<stime<<endl;
cout<<new_time<<endl;

但它们都打印 stime :just only hour for example 10

并打印new_time:例如10:20:15

Answer 1

由于分隔符“:”，您的字符串流无法正常工作。你需要绕过它。试试下面的代码:

string new_time;
new_time = CurrentTime();
std::string finalstring;
std::string delim = ":";
size_t pos = 0;
while ((pos = new_time.find(delim)) != std::string::npos)
{
    finalstring += new_time.substr(0, pos);
    new_time.erase(0, pos + delim.length());
}

stringstream strValue;
strValue << finalstring;
strValue << new_time;
unsigned int stime;
strValue >> stime;
cout << stime << endl;