java - Android:切换按钮打开:显示 fragment 关闭:隐藏 fragment

Question

我想切换按钮以在单击它时显示我的 fragment ，以及当我再次单击它以删除或隐藏我的 fragment 时。基本上〜开:炫耀:隐藏

@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
    Shower_fragment shower_fragment = new Shower_fragment();
    android.app.FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
    fragmentTransaction.add(R.id.linear_shower, shower_fragment, "Shower");
    if(isChecked){
        fragmentTransaction.show(shower_fragment);
        fragmentTransaction.commit();
    }else{
        fragmentTransaction.hide(shower_fragment);
        fragmentTransaction.commit();

    }
}

Answer 1

我认为你忘记调用 getFragmentManager();

Override public void onCheckedChanged(CompoundButton buttonView, boolean isChecked)
{ 
  Shower_fragment shower_fragment = new Shower_fragment();
  FragmentManager fm = getFragmentManager();

  if(null == fm){return;}
  if(isChecked)
  { 
     fm.beginTransaction();
       .add(R.id.linear_shower, shower_fragment, "Shower");
       .show()
       .commit(); 
  }else
  {  

    fm.beginTransaction();
       .add(R.id.linear_shower, shower_fragment, "Shower");
       .hide()
       .commit(); 
  } 
}