C++:我应该如何重新排列这段代码，以便循环检查这两种情况？

Question

我正在用 C++ 编写老虎机程序作为类作业。该程序应该占您总信用额的一定百分比(从 1000.00 开始)并生成三个随机数来表示三个插槽号。如果所有三个数字都匹配，则用户获胜。只要用户还有积分，游戏就会继续进行，程序应该始终询问用户是否要继续。

我基本上已经获得了程序运行所需的一切，但我的问题是，每当我玩游戏并获得匹配时，它不会提示用户输入更多点数。相反，它只是结束程序。我认为这与我编写 while 循环的方式有关，因为该条件仅适用于数字不匹配的情况，并且由于它们不匹配，因此无法检查循环中的第一个 if 语句.我尝试使用 do-while，但情况相同。我如何重新排列代码，以便即使用户赢了，它也会提示用户再次下注？

#include <ctime>
#include <cstdlib>
#include <iostream>
#include <iomanip>

using namespace std;

/* Start: Do Not Change */
const int MAX = 5; 
const int MIN = 1;

// This function takes tree ints as parameters
// and sets them to a random number
int spin(int & n1, int & n2, int & n3)
{
    n1 = rand()%(MAX-MIN)+MIN;
    n2 = rand()%(MAX-MIN)+MIN;
    n3 = rand()%(MAX-MIN)+MIN;
}
/* End: Do Not Change */

int main()
{
    int slot1, slot2, slot3;
    double percent;
    double credits = 1000.00;
    char keepPlaying; 

    srand (time(NULL));

    cout << "Welcome to the slots, you have 1,000.00 credits.\n"
    << "What percentage of credits do you want to bet(0-1)? ";

    cin >> percent; 
    spin(slot1, slot2, slot3); // At this point slot1-3 all have a random value between 1 and 5
                                //spin function 
    cout << "Slot value = " << slot1 << "-" << slot2 << "-" << slot3 << endl;

    while (slot1 != slot2 || slot1 != slot3 || slot2 != slot3)
    {
        if (slot1 == slot2 && slot1 == slot3 && slot2 == slot3)
        {
            cout << "\tYou won " << fixed << setprecision(2) << credits *   percent << " credits!\n";
            credits += (credits * percent); 

            cout << "Continue (y/n)? "; 
            cin >> keepPlaying;

            if (keepPlaying == 'y')
            {
               cout << "You have " << credits << " credits left.\n"; 
               cout << "What percentage of credits do you want to bet(0-1)? ";

                cin >> percent; 

                spin(slot1, slot2, slot3);
                cout << "Slot value = " << slot1 << "-" << slot2 << "-" << slot3 << endl; 

                continue; 
            }

            else if (keepPlaying == 'n')
            {
                cout << "You are leaving with " << credits << " credits." <<  endl; 
                return 0; 
            }
        }

        else
        {
            cout << "\tSorry, you lost " << fixed << setprecision(2) <<  credits * percent << " credits." << endl; 
            credits -= (credits * percent); 

            cout << "Continue (y/n)? "; 
            cin >> keepPlaying;

            if (keepPlaying == 'y' && credits != 0)
            {
                cout << "You have " << credits << " credits left.\n"; 
                cout << "What percentage of credits do you want to bet(0-1)? ";

                cin >> percent; 

                spin(slot1, slot2, slot3);
                cout << "Slot value = " << slot1 << "-" << slot2 << "-" << slot3 << endl;

                continue; 
            }

            else if (keepPlaying == 'y' && credits == 0)
            {
                cout << "Get out of here bum!" << endl; 
                return 0; 
            }

            else if (keepPlaying == 'n')
            {
                cout << "You are leaving with " << fixed << setprecision(2) << credits << " credits." << endl; 
                return 0; 
            }
        }
    }

    return 0; 
}`

Answer 1

试一试:

#include <ctime>
#include <cstdlib>
#include <iostream>
#include <iomanip>

using namespace std;

/* Start: Do Not Change */
const int MAX = 5; 
const int MIN = 1;

// This function takes tree ints as parameters
// and sets them to a random number
void spin(int & n1, int & n2, int & n3)
{
    n1 = rand()%(MAX-MIN)+MIN;
    n2 = rand()%(MAX-MIN)+MIN;
    n3 = rand()%(MAX-MIN)+MIN;
}
/* End: Do Not Change */

// How many credits the user has to play with
double credits = 1000.00; // 1000 is the starting point

void doGame(){
    int slot1, slot2, slot3;
    double percent;
    double dCreditsWagered;
    cout << "What percentage of credits do you want to bet(0-1)? ";

    cin >> percent;
    dCreditsWagered = credits*percent;

    spin(slot1, slot2, slot3); // At this point slot1-3 all have a random value between 1 and 5
                                //spin function
    cout << "Slot value = " << slot1 << "-" << slot2 << "-" << slot3 << endl;
    // Check if all slots are equal:
    if( (slot1 == slot2) && (slot1 == slot3)){
        // User won!
        cout << "\tYou won " << fixed << setprecision(2) <<  dCreditsWagered << " credits!" << endl;
        credits += dCreditsWagered; 
    } else {
        // User lost :(
        cout << "\tSorry, you lost " << fixed << setprecision(2) <<  dCreditsWagered << " credits." << endl; 
        credits -= dCreditsWagered; 
    }
}

int main(){
    char keepPlaying;

    srand (time(NULL));

    cout << "Welcome to the slots, you have 1,000.00 credits." << endl;

     do{
        doGame();
        cout << "Continue (y/n)? "; 
        cin >> keepPlaying;
        if (keepPlaying == 'y' && credits > 0) {
            // User would like to play another round
            cout << "You have " << credits << " credits left." << endl; 

        } else if(keepPlaying=='y' && credits <= 0){ // credits should never be < 0, but hey, doesn't hurt to check, right?
            // User does not have enough credits to continue playing:
            cout << "Get out of here you bum!" << endl;
            break;
        }else if (keepPlaying == 'n') {
             // User would like to quit
             cout << "You are leaving with " << credits << " credits." <<  endl; 
             break;
        }

     }while(true);

     return 0; 
}

我将您的实际游戏逻辑移到了名为 doGame() 的函数中。运行时，游戏会进入无限循环，执行 doGame() 然后检查用户是否想继续玩。如果用户想继续玩并且他们还有剩余的积分，循环将重新开始(因此 doGame() 将再次被调用。)如果用户选择退出或者如果用户不在学分并且他们尝试再次玩，代码将跳出 do-while 循环。

我还没有测试过这段代码，所以如果您发现错误，请告诉我，以便我进行修复。

编辑:刚刚编译和测试。我发现了两个错误。 #1，你的 int spin(int &n1, int &n2, int &n3) 函数被声明为返回一个 int，但它没有返回任何东西。 #2，我在 }while(true) 之后少了一个分号(语法错误)。

除了这两个错误之外，代码似乎按预期执行。理想情况下，应该添加一个名为 bool keepPlaying() 的函数，它会提示用户继续播放，然后验证用户的输入是 y 还是 n(如果他们输入了其他任何内容，则再次提示他们)，但我会把它留给你 :P