c++ - 交换字符串数组中的字符串

Question

不确定我做的对不对。但我试图显示输出 cat the sideways ran 而不是 the cat ransideways。

#include <string>
#include <iostream>
using namespace std;

void doSwap(string string1, string string2);

int main() {
    string theArray[5] = {"the", "cat", "ran", "sideways"};
    int i;
    for (i = 0; i < 4; i++) {
        doSwap(theArray[i], theArray[i+1]);
        cout << theArray[i] << " ";
    }
}

void doSwap (string string1, string string2) {
    string temp;
    temp = string1;
    string1 = string2;
    string2 = temp;
}

不确定我做的是否正确。

Answer 1

您应该通过引用传递字符串，因为您正在改变它们。编写代码的方式是发送要交换的字符串的临时拷贝，实际上是交换拷贝，而不是在数组中交换它们。更新代码:

#include <string>
#include <iostream>
using namespace std;

void doSwap(string string1, string string2);

int main() {
    string theArray[] = {"the", "cat", "ran", "sideways"};
    int i;
    for (i = 0; i < (sizeof theArray)/sizeof(string); i++) {
        doSwap(theArray[i], theArray[i+1]);
        cout << theArray[i] << " ";
    }
}

void doSwap (string &string1, string &string2) {
    string temp;
    temp = string1;
    string1 = string2;
    string2 = temp;
}