java - 扫描仪再次出现问题

Question

我在尝试使用 Java 中的扫描程序时遇到了困难。

我尽力查找这段代码的错误，但没找到。

我运行它，然后程序允许我选择一个“代码”以及“单词”和“类别”(如果代码是 d)。当我尝试输入另一个代码时，程序进入无限循环。请大家指出我的错误可能在哪里？

import java.util.*;
public class GrammarChecker {       
  public static void main(String [ ] args) 
  {
   Dicionary dicionary = new Dicionary();
   Grammar grammar = new Grammar();
   Item a;
   String word, category, specification;
   int count = 0;
   char code;
   Scanner entry = new Scanner(System.in); 
   System.out.println("What is the code?");
   code = entry.nextLine().charAt(0);                 
   switch(code)
   {
      case 'd':
          System.out.println ("How many words your dicionary will have");
          count = entry.nextInt();
          entry.nextLine(); 
          for(int i = 0; i < count; count--) 
          {
            System.out.println ("What is the word?");
            word = entry.nextLine();
            System.out.println ("What is the category?");
            category = entry.nextLine(); 
            a = new Item (word, category);
            dicionary.listWords(a);

          }
      break;

      case 'g':   
         System.out.println ("How many lines are you going to use to specify your grammar?");
         count = entry.nextInt();
         entry.nextLine();

         for(int j = 0; j < count; count--) 
         {
          System.out.println ("What is the specification?");
          specification = entry.nextLine(); 
          grammar.listStructure(specification);

         } 

      break;

      case 'c':
          System.out.println ("I only accept d ou g");
      break;

      case 'f':
            System.out.println ("I only accept d ou g");
      break;
    }

    System.out.println("Would you like to enter another code?");
    code = entry.nextLine().charAt(0);
    entry.nextLine();

  }  
}

Answer 1

您的代码中没有循环来读取多行。所以它似乎在最后陷入了 entry.nextLine(); 。此外，您还为从未使用过的 code 分配了一个新值。尝试这样的事情:

loop: while (entry.hasNextLine()) {
    code = entry.nextLine().charAt(0);
    switch (code) {
        // handle each case except 'e'
    case 'e':
        break loop;
    }
    System.out.println("Would you like to enter another code?");
    System.out.println("Otherwise press e");
}