java - 如何将数组转换为不带逗号/括号的字符串格式并添加括号作为值

Question

我想获取我生成的随机值数组，并在相同数字的最长运行之外打印上述数组并用括号括起来。例如，如果数组是 [0,1,1,1,2,4,7,4] 我想接收 0(111)2474 作为输出。

这是我迄今为止的代码。

import java.util.Random;
import java.util.Arrays;

/**
 * Write a description of class ArrayRunner1 here.
 * 
 * @author Ibrahim Khan
 * @version (a version number or a date)
 */
public class ArrayRunner1 {

    /**
     * This method will generate my random numbers for my array. 
     * @param min minimum random value wanted
     * @param max maximum random value wanted
     * @return randomNum a random number between 1 and 6 inclusive
     */
    public static int randInt(int min, int max) {
        Random rand = new Random();
        int randomNum = rand.nextInt((max - min) + 1) + min;
        return randomNum;
    }

    public static void main(String[] args) {
        System.out.println("\f");


        //Part 1 - Generate a random array of length 40 with random 1-6 inclusive
        int[] array1 = new int[40];
        for (int i = 0; i < array1.length; i++) {
            array1[i] = randInt(1, 6);
        }
        System.out.println(Arrays.toString(array1));

        //Counts and RETURN: reports how many times each number is present
        int counter1 = 0;
        int counter2 = 0;
        int counter3 = 0;
        int counter4 = 0;
        int counter5 = 0;
        int counter6 = 0;
        for (int i = 0; i < array1.length; i++) {
            if (array1[i] == 1) {
                counter1++;
            }
            if (array1[i] == 2) {
                counter2++;
            }
            if (array1[i] == 3) {
                counter3++;
            }
            if (array1[i] == 4) {
                counter4++;
            }
            if (array1[i] == 5) {
                counter5++;
            }
            if (array1[i] == 6) {
                counter6++;
            }
        }

        System.out.println("There are " + counter1 + " ones.");
        System.out.println("There are " + counter2 + " twos.");
        System.out.println("There are " + counter3 + " threes.");
        System.out.println("There are " + counter4 + " fours.");
        System.out.println("There are " + counter5 + " fives.");
        System.out.println("There are " + counter6 + " sixes.");

        //Counts the longest run of the same number. A run continues only when consecutive numbers have the same value.   
        //RETURN: The repeated number and the length of the run is then printed
        int counter = 1;
        int runMax = 1;
        int runMin = 0;
        int variableNum = 0;
        int startCounter = 0;
        int endCounter = 0;

        for (int i = 0; i < array1.length - 1; i++) {

            if (array1[i] == array1[i + 1]) {
                counter++;

                if (counter >= runMax {
                    runMax = counter;
                    runMin = i - counter + 1;
                    variableNum = array1[i];
                    startCounter = i - counter + 2;
                    endCounter = i + counter - 1;
                }
                } else {
                    counter = 1;

                }


            }
            System.out.println("The longest run is " + runMax + " times and the number is " + variableNum + ". ");
            System.out.println("The run starts at " + startCounter + " and ends at " + endCounter);




            //Prints the array with parentheses outside the longest run, if there is more than one max run, use the last one. 
        }
    }

Answer 1

试试这个代码:

import java.util.Arrays;
import java.util.Random;

public class Snippet {
    /**
     * This method will generate my random numbers for my array.
     * 
     * @param min
     *            minimum random value wanted
     * @param max
     *            maximum random value wanted
     * @return randomNum a random number between 1 and 6 inclusive
     */
    public static int randInt(int min, int max) {
        Random rand = new Random();
        int randomNum = rand.nextInt((max - min) + 1) + min;
        return randomNum;
    }

    public static void main(String[] args) {
        System.out.println("\f");

        // Part 1 - Generate a random array of length 40 with random 1-6
        // inclusive
        int[] array1 = new int[40];
        for (int i = 0; i < array1.length; i++) {
            array1[i] = randInt(1, 6);
        }
        System.out.println(Arrays.toString(array1));

        // Counts and RETURN: reports how many times each number is present
        int counter1 = 0;
        int counter2 = 0;
        int counter3 = 0;
        int counter4 = 0;
        int counter5 = 0;
        int counter6 = 0;
        for (int i = 0; i < array1.length; i++) {
            if (array1[i] == 1) {
                counter1++;
            }
            if (array1[i] == 2) {
                counter2++;
            }
            if (array1[i] == 3) {
                counter3++;
            }
            if (array1[i] == 4) {
                counter4++;
            }
            if (array1[i] == 5) {
                counter5++;
            }
            if (array1[i] == 6) {
                counter6++;
            }
        }

        System.out.println("There are " + counter1 + " ones.");
        System.out.println("There are " + counter2 + " twos.");
        System.out.println("There are " + counter3 + " threes.");
        System.out.println("There are " + counter4 + " fours.");
        System.out.println("There are " + counter5 + " fives.");
        System.out.println("There are " + counter6 + " sixes.");

        // Counts the longest run of the same number. A run continues only when
        // consecutive numbers have the same value.
        // RETURN: The repeated number and the length of the run is then printed
        int counter = 1;
        int runMax = 0;
        int runMin = 0;
        int variableNum = 0;
        int startCounter = 0;
        int endCounter = 0;

        for (int i = 0; i < array1.length - 1; i++) {

            if (array1[i] == array1[i + 1]) {
                counter++;

                if (counter >= runMax) {
                    runMax = counter;
                    startCounter = i - counter +2;
                    // runMin = i-counter+1;
                    variableNum = array1[i];
                    endCounter = i+1;
                }
            } else {
                counter = 1;

            }

        }
        System.out.println("The longest run is " + runMax
                + " times and the number is " + variableNum + ". ");
        System.out.println("The run starts at " + startCounter
                + " and ends at " + endCounter);

        for (int i = 0; i < array1.length; i++) {
            if (i==startCounter) {
                System.out.print("(");
            }
            System.out.print(array1[i]);
            if (i==endCounter) {
                System.out.print(")");
            }
        }
        System.out.println();

        // Prints the array with parentheses outside the longest run, if there
        // is more than one max run, use the last one.
    }
}