java - 在数组中搜索字符

Question

我正在创建一个java程序，并且一直坚持在数组中搜索字符的概念。

该代码用于创建一个刽子手游戏，其中一部分将显示部分完成的刽子手、一个字母表和一组空格(“_”)，用于表示需要猜测的单词的长度。每次猜测后，我需要从字母表中取出猜测的字母(这是我现在正在做的部分)，如果猜测正确，则用该字母替换单词中的空白，或者如果猜测错误，则完成刽子手的另一部分。

我之前只创建了代码来搜索数组中的数字，而不是字符。我一直在翻阅我的书和互联网，但找不到解决方案。

没有人知道这样做的方法或者我可以在哪里找到方法吗？

抱歉，我已经发布了有关此作业的问题，但几天后就要到期，我正在努力。

这是到目前为止我的代码(我正在努力解决的部分位于最底部):

public static void main(String[] args)
{
    String[] words =
    {
        "javascript", "declaration", "object", "program", "failing"
    };
    //generate random word from list
    Random rnd = new Random();

    String rndWord = words[rnd.nextInt(words.length)];

    //gets length of generated word
    char[] displayArray = new char[rndWord.length()];
    //displays "_" for number of chars in word
    for (int i = 0; i < rndWord.length(); i++)
    {
        displayArray[i] = '_';
    }

    char[] alphabet =
    {
        'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
        +'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w',
        +'x', 'y', 'z'
    };
    String hangman
            = "Let's Play Hangman!!" + "\n"
            + "-------------" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "\n" + Arrays.toString(displayArray) + "\n"
            + "       ";

    JOptionPane.showMessageDialog(null, hangman + " "
            + Arrays.toString(alphabet) + " ");
}

//get letter
public static char guess()
{
    String guessStr = JOptionPane.showInputDialog("Enter a letter to guess: ");

    // check if have at least one letter
    if (guessStr.length() > 0)
    {

    }
    char guessChar = guessStr.charAt(0);
    return guessChar;
}

//remove guess from alphabet
private char[] getCharArray(char[] array)
{
   //this is the part I'm not sure about
}

Answer 1

您可以使用contains()方法来查找列表中的字符。通过 char c = GuessStr.toLowerCase().toCharArray()[0]; 从玩家输入的 guessStr 获取字符。并通过 if (guessedCharList.contains(new Character(c))) 在 List 中搜索它。 List只能存储对象，因此我们必须通过new Character(c)将char原始类型转换为对象Character。

下面的代码将会帮助你!但你应该对其进行优化。

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Random;

import javax.swing.JOptionPane;

public class HangMan {

    private static List<Character> guessedCharList = new ArrayList<Character>();
    private static List<Character> validCharList = new ArrayList<Character>();
    private static String rndWord = null;

    private static int numberOfWrongGuess = 0;

    public static void main(String[] args) {
        String[] words = { "javascript", "declaration", "object", "program",
                "failing" };
        // generate random word from list
        Random rnd = new Random();

        rndWord = words[rnd.nextInt(words.length)];
        System.out.println(rndWord);
        // gets length of generated word
        char[] displayArray = new char[rndWord.length()];
        // displays "_" for number of chars in word

        for (int i = 0; i < rndWord.length(); i++) {
            displayArray[i] = '_';
        }
        char[] alphabet = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
                +'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
                'w', +'x', 'y', 'z' };

        String hangman = null;
        boolean finished = false;
        do {

            hangman = "Let's Play Hangman!!" + "\n" + "-------------" + "\n"
                    + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|"
                    + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "\n"
                    + Arrays.toString(displayArray) + "\n" + "       ";

            JOptionPane.showMessageDialog(null,
                    hangman + " " + Arrays.toString(alphabet) + " ");
            guess();

            for (int i = 0; i < rndWord.length(); i++) {

                if (validCharList.contains(rndWord.charAt(i)))
                    displayArray[i] = rndWord.charAt(i);
                else
                    displayArray[i] = '_';
            }

            for (char c : displayArray) {
                if (c == '_') {
                    finished = false;
                    break;
                } else
                    finished = true;
            }

            if (numberOfWrongGuess >= 5) { // 5 wrong guess: "he was hanged."
                JOptionPane.showMessageDialog(null, "Man was hanged!");
                finished = true;
            }
        } while (!finished);

        hangman = "Let's Play Hangman!!" + "\n" + "-------------" + "\n" + "|"
                + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n"
                + "|" + "\n" + "|" + "\n" + "|" + "\n" + "\n"
                + Arrays.toString(displayArray) + "\n" + "       ";
        JOptionPane.showMessageDialog(null,
                hangman + " " + Arrays.toString(alphabet) + " ");
    }

    // get letter
    public static String guess() {
        String guessStr = "";

        while (guessStr == null || guessStr.trim().isEmpty()
                || guessStr.length() > 1) {
            guessStr = JOptionPane.showInputDialog("Enter a letter to guess: ");
        }

        char c = guessStr.toLowerCase().toCharArray()[0];

        if (guessedCharList.contains(new Character(c))) {
            JOptionPane
                    .showMessageDialog(null, "You already give that answer!");
            guess();
        }

        guessedCharList.add(new Character(c));

        if (rndWord.contains(c + "")) {
            validCharList.add(new Character(c));
            return c + "";
        } else {
            numberOfWrongGuess++;
            return "";
        }
    }
}