java - 尝试关闭控制台时输入不匹配错误

Question

我编写了一个非常基本的程序，有 3 个选项。在执行代码的“退出”部分时，我收到一个InputMismatchError。我知道这是因为当我/用户给它一个字符串时，程序需要一个整数。我只是想知道如何设置这样的东西。我也尝试过 string to char 方法，但这也给了我同样的错误。

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;




    static Scanner S = new Scanner(System.in);
    public static void main(String[] args)  throws IOException
    {
        int DisJ, ISJ, User;

        ISJ = 1;
        DisJ = 2;
        String input = "";

        // change print outs to appropriate names::::
        System.out.println("--Main Menu--");
        System.out.println("Display Journeys:" + ISJ);
        System.out.println("Suitable Journeys:" + DisJ);
        System.out.println("Quit: " );

        //User = S.next().charAt(0);
        User = S.nextInt();
        if (User == 1)
        {

            System.out.println("You have selected Display Journeys");
            try 
            (BufferedReader ReadFile = new BufferedReader(new FileReader("E:\\input.txt"))) 
            {
                   String line = null;
                   while ((line = ReadFile.readLine()) != null) 
                   {
                   System.out.println(line);
                   }    
            }

        }

        else if (User ==2)
        {
            System.out.println("You have selected Suitable Journeys");
        }
        System.out.println("Specify Destination: ");
        String destination = S.next();
        System.out.println("Specify Max Time (HH:MM): ");
        String specificTime = S.next();
                // This assigns the first two integers to the string hours
        String hours = specificTime.substring(0,2);
                //This assigns the last two integers to the string minutes
        String minutes = specificTime.substring(3,5);
                //integer.parseInt converts the string into an integer
        int hours1 = Integer.parseInt(hours);
                //integer.parseInt converts the string into an integer
        int minutes1 = Integer.parseInt(minutes);
        int Time;
                // Equation to convert the hh:mm into minutes
        Time = (60 * hours1) + minutes1;            
        System.out.println("Specify number of changes");
        int Changes = S.nextInt();

        System.out.println( "Destination selected: " + input + "Minutes specified: "  + Time + "," + "Number of changes: " + Changes);

        int quit;
        String Quit = S.next();

        if (Quit.equals("Quit")) {

            System.out.println("Goodbye!");
            System.exit(0);

        } 
        try {
            quit = Integer.parseInt(Quit);
        }
        catch (Exception e)
        {
    System.out.println("Type Quit to leave");
        }
    }
}

Answer 1

您的问题是您无法使 if 语句中的参数成立吗？尝试将其设置为 boolean 值而不是 int/string，并且在整个代码中将 quit 更改为 true/false 而不是数字/字符串。

编辑:哦，我明白了。所以你只想让用户按下一个键就会退出，就像“请输入 Y 退出程序”您设置了扫描仪吗？