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java - 单选按钮总是将默认值保存到 sqlite 中

转载 作者:太空宇宙 更新时间:2023-11-04 13:05:01 24 4
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我的问题是,每当我检查数据库查看患者时,即使我检查女性,我也会看到性别是男性。 这是代码: fragment 病人.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="wrap_content"
android:layout_height="match_parent"
android:orientation="vertical" >

<LinearLayout
android:layout_width="match_parent"
android:layout_height="54dp"
android:orientation="horizontal" >

<EditText
android:id="@+id/name_text"
android:layout_width="143dp"
android:layout_height="wrap_content"
android:layout_marginLeft="16dp"
android:layout_marginRight="16dp"
android:ems="10"
android:hint="@string/name_text_hint" />

<EditText
android:id="@+id/familyname_text"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginLeft="16dp"
android:hint="@string/familyname_text_hint" />
</LinearLayout>

<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="horizontal" >

<EditText
android:id="@+id/date_text"
android:layout_width="wrap_content"
android:layout_height="match_parent"
android:ems="10"
android:hint="@string/date_text_hint" >
</EditText>
</LinearLayout>

<RadioGroup
android:id="@+id/myRadioGroup"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_below="@+id/text"
android:checkedButton="@+id/male_text" >


<RadioButton
android:id="@+id/female_text"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/female_text" />

<RadioButton
android:id="@+id/male_text"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/male_text" />
</RadioGroup>


<EditText
android:id="@+id/address_text"
android:layout_width="348dp"
android:layout_height="wrap_content"
android:ems="10"
android:hint="@string/address_text_hint" />

<LinearLayout
android:layout_width="340dp"
android:layout_height="57dp"
android:orientation="horizontal" >

<EditText
android:id="@+id/phone_text"
android:layout_width="143dp"
android:layout_height="wrap_content"
android:hint="@string/phone_text_hint" />

<EditText
android:id="@+id/email_text"
android:layout_width="213dp"
android:layout_height="wrap_content"
android:hint="@string/email_text_hint" />
</LinearLayout>

<Button
android:id="@+id/save_button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_gravity="right"
android:text="@string/save_button" />

</LinearLayout>

Patientfragment.java

package com.example.appointapp;

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.Button;
import android.widget.EditText;
import android.widget.RadioButton;
import android.widget.RadioGroup;
import android.widget.Toast;

public class PatientFragment extends Fragment {
DatabaseHelper myDB;
EditText editName,editFamilyname,editDob,editAddress,editPhonenb,editEmail;
Button btnSave, selectedRadioButton;
RadioButton radioB;
RadioGroup radioG;
private Patient mPatient;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mPatient= new Patient();

}


@Override
public View onCreateView(LayoutInflater inflater, ViewGroup parent, Bundle savedInstanceState){
View v = inflater.inflate(R.layout.fragment_patient, parent, false);
myDB = new DatabaseHelper(getActivity());
editName = (EditText)v.findViewById(R.id.name_text);
editFamilyname = (EditText)v.findViewById(R.id.familyname_text);
editDob = (EditText)v.findViewById(R.id.date_text);
editAddress = (EditText)v.findViewById(R.id.address_text);
editPhonenb = (EditText)v.findViewById(R.id.phone_text);
editEmail = (EditText)v.findViewById(R.id.email_text);
btnSave = (Button)v.findViewById(R.id.save_button);
radioG = (RadioGroup)v.findViewById(R.id.myRadioGroup);

int selectedId = radioG.getCheckedRadioButtonId();
if(selectedId != -1) {
selectedRadioButton = (RadioButton)v.findViewById(selectedId);

}


AddData();

return v;
}


public void AddData() {
btnSave.setOnClickListener(
new View.OnClickListener(){
@Override
public void onClick(View v){



boolean isInserted = myDB.insertData(editName.getText().toString() ,
editFamilyname.getText().toString() ,
editDob.getText().toString() ,
editAddress.getText().toString() ,
editPhonenb.getText().toString() ,
editEmail.getText().toString(),
selectedRadioButton.getText().toString()) ;
if(isInserted == true)
Toast.makeText(getActivity(), "Patient inserted", Toast.LENGTH_LONG).show();
else
Toast.makeText(getActivity(), "Patient not inserted", Toast.LENGTH_LONG).show();
}
}
);

}
}

请帮忙解决我的问题

最佳答案

解决方案:1

onCreateView()view 对象声明为全局对象。

View view;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup parent, Bundle savedInstanceState){
view = inflater.inflate(R.layout.fragment_patient, parent, false);
...
}

并且您的radioG.getCheckedRadioButtonId()代码应位于onClick()

@Override
public void onClick(View v){

int selectedId = radioG.getCheckedRadioButtonId();
if(selectedId != -1) {
selectedRadioButton = (RadioButton)view.findViewById(selectedId);
}

boolean isInserted = myDB.insertData(editName.getText().toString() ,
editFamilyname.getText().toString() ,
editDob.getText().toString() ,
....
}

解决方案:2

  1. 创建两个RadioButton的对象
  2. 将其与您在 onClick() 中选择的 RadioButton 进行比较

    @Override
    public void onClick(View v){

    int selectedId = radioG.getCheckedRadioButtonId();
    if(selectedId == radio1.getId()) {
    selectedRadioButton = radio1;
    }
    else if(selectedId == radio2.getId()) {
    selectedRadioButton = radio2;
    }

关于java - 单选按钮总是将默认值保存到 sqlite 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34564293/

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