linux - 如何在 Bash 中运行多次相同的代码

Question

如何多次运行同一代码？比如12次？

 sed -n 1,1p 00-02.txt | sed -e 's/^/<video length="-1" src="mp4:/' \
                          -e 's/$/" start="0"><\/video>/' >>playlist.txt

    echo -e "$(sed -e '1,1d' 00-02.txt)\n" > 00-02.txt

    cat 00-02.txt | sed '/^$/d' >> 00-02a.txt

    rm 00-02.txt

    mv 00-02a.txt 00-02.txt

    sed -n 1,1p spot.txt | sed -e 's/^/<video length="-1" src="mp4:/' \
                          -e 's/$/" start="0"><\/video>/' >>playlist.txt

    echo -e "$(sed -e '1,1d' spot.txt)\n" > spot.txt

    cat spot.txt | sed '/^$/d' >> spota.txt

    rm spot.txt

mv spota.txt spot.txt

所有爱的代码必须复制N次

有点像

for n in {1..12}; **ALL THE COMMANDS BELOVE**; done

但它不适用于多行命令。

有什么问题吗？

Answer 1

使用 while 循环和计数器:

#!/bin/bash

iterations=12
count=0

while [ "$count" -lt "$iterations" ]
do
    sed -n 1,1p 00-02.txt | sed -e 's/^/<video length="-1" src="mp4:/' \
                      -e 's/$/" start="0"><\/video>/' >>playlist.txt

    echo -e "$(sed -e '1,1d' 00-02.txt)\n" > 00-02.txt

    cat 00-02.txt | sed '/^$/d' >> 00-02a.txt

    rm 00-02.txt

    mv 00-02a.txt 00-02.txt

    sed -n 1,1p spot.txt | sed -e 's/^/<video length="-1" src="mp4:/' \
                      -e 's/$/" start="0"><\/video>/' >>playlist.txt

    echo -e "$(sed -e '1,1d' spot.txt)\n" > spot.txt

    cat spot.txt | sed '/^$/d' >> spota.txt

    rm spot.txt

    mv spota.txt spot.txt
    count=$(( count + 1 ))
done