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c - 命名管道 Linux

转载 作者:太空宇宙 更新时间:2023-11-04 13:00:46 25 4
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我尝试运行这段代码,但是当我从管道读取时,没有任何信息:

Statitics:
Hora de inicio:(null)
Total pedidos:0
Pedidos recusados:0
Dominios locais:0
Dominios externos:0
Hora atual:17:5:14

我不知道出了什么问题...我需要帮助。

typedef struct{
int pedidos;
int loc;
int ext;
int rej;
char* start;
} esta;
int fdpipe;
fd_set write_set;

//PROCESS 1--------------------------------------------------------------

作者:

esta* estatisticas;

estatisticas=(esta* )malloc(sizeof(esta));
estatisticas->start=convertTime(time(NULL));

estatisticas->ext=1;
estatisticas->loc=1;
estatisticas->rej=1;
estatisticas->pedidos=1;

if (mkfifo(mpconfs->pipe_stats,0600)<0)
{
perror("Cannot create pipe: ");
exit(0);
}
//escrever no pipe
if ((fdpipe=open(mpconfs->pipe_stats, O_WRONLY)) < 0)
{
perror("Cannot open pipe for writing: ");
exit(0);
}

while(1) {
//escrever no pipe
FD_ZERO(&write_set);

FD_SET(fdpipe, &write_set);



if (select(fdpipe+1, NULL, &write_set, NULL, NULL)>0) {
if(FD_ISSET(fdpipe,&write_set)){
write(fdpipe, &estatisticas, sizeof(esta));
}
}
}

读者: //进程2-------------------------------------------- --------------

fd_set read_set;
esta* estatisticas;
signal(SIGINT,catch_ctrlcProcEsts);

sleep(2);
if ((fdpipe=open(mpconfs->pipe_stats, O_RDWR)) < 0)
{
perror("Cannot open pipe for reading: ");
exit(0);
}

while(1){

FD_ZERO(&read_set);
// prepares read set to "listen" to the following FD
FD_SET(fdpipe, &read_set);
if (select(fdpipe+1, &read_set, NULL, NULL, NULL)>0) {
if(FD_ISSET(fdpipe,&read_set)){

read(fdpipe, &estatisticas, sizeof(esta));
imprimeStats(estatisticas);
}
}

}
}

void imprimeStats(esta* estatisticas){
char *horaAtual=convertTime(time(NULL));
printf("\nStatitics:\n");
printf("Hora de inicio:%s\n",estatisticas->start);
printf("Total pedidos:%d\n",estatisticas->pedidos);
printf("Pedidos recusados:%d\n",estatisticas->rej);
printf("Dominios locais:%d\n",estatisticas->loc);
printf("Dominios externos:%d\n",estatisticas->ext);
printf("Hora atual:%s\n\n",horaAtual);
}

char *convertTime(time_t time){
char *res;
int h, min, sec;
res=(char*)malloc(9*sizeof(char));
res[0]='\0';

h=(time/3600);
min=(time-3600*h)/60;
sec = time%60;
h=h%24;
sprintf(res,"%d:%d:%d", h, min, sec);
return res;
}

我想我什么都不会忘记。

最佳答案

你可能误用了读写:你写了 read(fdpipe, &estatisticas, sizeof(esta)); 但声明了 esta* estatisticas; 因此你实际上发送了你分配的地址加上一些垃圾(undefined behaiour)

你可能打算写:read(fdpipe, estatisticas, sizeof(*estatisticas))

顺便说一句,你应该检查你读取的字节数,因为读取并不总是读取你要求的所有字节(可能更少)

小心,你在写入端犯了同样的错误,不要忘记在那里修复它。

关于c - 命名管道 Linux,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33962958/

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