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c++ - 某行代码不执行

转载 作者:太空宇宙 更新时间:2023-11-04 12:54:56 24 4
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我的程序的内容对于这个问题并不重要,但我们几乎使用类和对象来保存信息。我的代码如下:

#include <iostream>
using namespace std;

class Car
{
private:
int carNumber;
bool loaded;
string reportingMark, kind, destination;
public:
void setUp(string reportingMark, int carNumber, string kind, bool
loaded, string destination);
void output();
};

void input(string &reportingMark, int &carNumber, string &kind, bool
&loaded, string &destination);

/* ******************** main ********************
*/
int main()
{
Car *ptr;

string reportingMark, kind, destination;
int carNumber;
bool loaded;

Car c = *new Car();
ptr = &c;
input(reportingMark, carNumber, kind, loaded, destination);
ptr->setUp(reportingMark, carNumber, kind, loaded, destination);
ptr->output();
return 0;
}
/* ******************** Member Functions ********************
*/

/* ******************** setUp ********************
Takes 5 parameters by value: reporting mark, car number, kind, loaded,
and destination
Inputs these paramaters into the Car class' variables
*/
void Car::setUp(string rm, int cn, string k, bool l, string d)
{
reportingMark = rm, carNumber = cn, kind = k, loaded = l,
destination = d;
}

/* ******************** output ********************
Prints the reporting mark, car number, kind, loaded, and destination
in a neat format
*/
void Car::output()
{
cout << "\n\nReporting Mark: " << reportingMark << "\nCar Number: "
<< carNumber << "\nKind: " << kind << "\nCar is loaded: " << loaded <<
"\Destination: " << destination << endl;
}
/* ******************** Global Functions ********************
*/

/* ******************** input ********************
Takes the reporting mark, car number, kind, loaded, and destination as
reference parameters
Asks the user to input these values
*/
void input(string &reportingMark, int &carNumber, string &kind, bool
&loaded, string &destination)
{
do
{
cout << "What is the Reporting Mark? (Between 2-4 characters) ";
getline(cin, reportingMark);
if(reportingMark.length() < 2 || reportingMark.length() > 4) cout << "invalid input, try again\n";
} while(reportingMark.length() < 2 || reportingMark.length() > 4);
cout << "What is the Car Number? ";
cin >> carNumber;
int carNumResponse;

do
{
cout << "What is the Kind? (Choose '1' for business, '2' for maintenance, or '3' for other) ";
cin >> carNumResponse;
if(carNumResponse < 1 || carNumResponse > 3) cout << "invalid input, try again\n";
} while(carNumResponse < 1 || carNumResponse > 3);
if(carNumResponse == 1) kind = "business";
if(carNumResponse == 2) kind = "maintenance";
if(carNumResponse == 3) kind = "other";

int loadedResponse;

do
{
cout << "Is the car loaded? (Type '1' if true and '2' if false) ";
cin >> loadedResponse;
if(loadedResponse < 1 || loadedResponse > 2) cout << "invalid input, try again\n";
} while(loadedResponse < 1 || loadedResponse > 2);
if(loadedResponse == 1) loaded = true;
if(loadedResponse == 2) loaded = false;

cout << "What is the Destination? ";
getline(cin, destination);
}

我程序的最后两行:

cout << "What is the Destination? ";
getline(cin, destination);

出于某种原因不让我输入任何内容。我是否错误地使用了 getline?它在程序的其他部分中的使用方式相同。感谢任何提供帮助的人!

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