java - 获取重定向uri的位置

Question

这是我的网址:

https://localhost.com.ua/oauth/authorize?client_id=SS&response_type=code&scope=N_FULL&access_type=offline&redirect_uri=http://localhost/

在 java 中发布该内容(http post 请求)后，它将被重定向到此 URI:

https://kuma.ruto/v1/0auth/grant?state=some&code=YrnYdnHdY

如何获取重定向的URI并获取code值？

下面是代码片段:

String data = "email=p@f.com&password=Airtel@2017"; URL url = new URL("https://login.something.com/v1/oauth/authorize?response_type=code&state=none&email=p@f.com&client_id=jkhsdhaskfhdash&password=Airtel@2017&redirect_uri=https://login.something.com&code=none");

                                     HttpURLConnection conn = (HttpURLConnection) url.openConnection();

                                     con.setDoOutput(true);
                                     OutputStreamWriter writer = new OutputStreamWriter(
                                                                     con.getOutputStream());
                                     writer.write(data);
                                     InputStream is = con.getInputStream();
                                     System.out.println( "redirected url: " + con.getURL() );


                                     BufferedReader br = new BufferedReader(new InputStreamReader(
                                                                     (conn.getInputStream())));
                                     System.out.println( "redirected url2: " + con.getURL() );

                                     String st = null;
                                     String output;
                                     System.out.println("Output from Server .... \n");
                                     while ((output = br.readLine()) != null) {
                                                     System.out.println(output);

                                                     st += output;
                                     }
                                     Spdfast111 test = new Spdfast111();
                                     Map<String, String> map=test.getFormParams(st);
                                     URL url1 = new URL("https://login.something.com/v1/oauth/grant?value_one="+map.get("value_one")+"&value_two="+map.get("value_two")+"redirected_uri=https://login.something.com/v1/oauth/token");
                                     System.out.println("==========================="+url1);
                                     HttpURLConnection con1 = (HttpURLConnection) url1.openConnection();

                                     System.out.println( "orignal url: " + con1.getURL() );
                                     con1.connect();
                                     System.out.println( "connected url: " + con1.getURL() );
                                     InputStream is1 = connn.getInputStream();
                                     System.out.println( "redirected url: " + con1.getURL() );
                                     is1.close();

Answer 1

您可以看一下以下示例:

https://github.com/mconf/bbb-java/blob/master/src/main/java/org/mconf/bbb/api/JoinServiceBase.java#L151

        HttpClient client = new DefaultHttpClient();
        HttpGet method = new HttpGet(joinUrl);
        HttpContext context = new BasicHttpContext();
        HttpResponse httpResponse = client.execute(method, context);
        if (httpResponse.getStatusLine().getStatusCode() != HttpStatus.SC_OK)
            log.debug("HTTP GET {} return {}", joinUrl, httpResponse.getStatusLine().getStatusCode());
        HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute( 
                ExecutionContext.HTTP_REQUEST);

        if (!currentReq.getURI().getPath().equals("/client/BigBlueButton.html")) {
            log.warn("It was redirected to {} instead of /client/BigBlueButton.html: the server was branded" +
                    " and the HTML name was changed, or it's an error. However, it will continue processing", currentReq.getURI().getPath());
        }

        HttpHost currentHost = (HttpHost) context.getAttribute( 
                ExecutionContext.HTTP_TARGET_HOST);
        String enterUrl = currentHost.toURI() + "/bigbluebutton/api/enter";