linux - 如何从命令行更改 Linux/Unix 中的目录结构？

Question

这是我想要做的:给定目录“XYZ”，我希望能够设置 XYZ，一旦在其中创建了新的子目录(“ABC”)，默认情况下该子目录包含 3子目录(“1”、“2”、“3”)。例如:ls -la/ABC/XYZ/将显示 3 个文件夹，而无需我手动创建这 3 个文件夹

Answer 1

使用inotify 来监控文件系统事件并在捕获'create driectory ABC in XYZ' 事件时执行相关操作。这是来自 http://onestraw.net/essay/inotify/ 的示例

#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <sys/inotify.h>

#define MONITOR_PATH    "/var/onestraw/"
#define MONITOR_MASK    IN_CREATE | IN_DELETE | IN_ACCESS | IN_MODIFY

inline void _err(const char *str)
{
    perror(str);
    exit(1);
}

inline void inotify_loop(int fd)
{
    char buf[4096];
    size_t len;
    struct inotify_event *event;
    while (1) {
        len = read(fd, buf, sizeof(buf));
        if (len < 0) {
            _err("read() failed");
        }
        for (event = (struct inotify_event *)buf;
             (char *)event < &buf[len];
             event =
             (struct inotify_event *)((char *)event + sizeof(*event) +
                          event->len)) {
            if (event->mask & IN_CREATE)
                printf("add %s\n", event->name);
            if (event->mask & IN_DELETE)
                printf("delete %s\n", event->name);
            if (event->mask & IN_ACCESS)
                printf("access %s\n", event->name);
            if (event->mask & IN_MODIFY)
                printf("modify %s\n", event->name);
        }
    }
}

int main(int argc, char *argv[])
{
    int fd;

    if ((fd = inotify_init()) < 0) {
        _err("inotify_init() failed");
    }
    //if (inotify_add_watch(fd, argv[1], MONITOR_MASK) < 0) {
    if (inotify_add_watch(fd, MONITOR_PATH, MONITOR_MASK) < 0) {
        _err("inotify_add_watch() failed");
    }

    inotify_loop(fd);
    return 0;
}