c++ - 当我按 enter 时程序不会继续

Question

我以前从未遇到过这个问题。当我按 enter 接受 userInput 时，程序不执行。有什么理由吗？

#include <iostream>
using namespace std;

struct node{
  char data;
  struct node* left;
  struct node* right;
};


struct node* newNode(int idata){
  struct node* node = new struct node;

  node -> data = idata;
  node -> left = NULL;
  node -> right = NULL;

  return node;
};

void getUserInfo(string &userInput, int &lengthString){
  cout << "A string that contains a dot(.) will be invalid!" << endl;
  cout << "Enter a string ->";
  cin >> userInput;

  // getting the length of string
  lengthString = userInput.length();
}

void stringToChar(char *& charArray, int &lengthString){
  for(int i = 0; i < lengthString; i++){
    cin >> *(charArray+i);
  }
}

int main(){
  string userInput;
  int lengthString = 0;

  char * charArray;
  charArray = new char [lengthString];

  getUserInfo(userInput, lengthString);

  stringToChar(charArray, lengthString);

  /*struct node *root= newNode(9);
  root ->left = newNode(20);
  (*root).right = newNode(3);
  cout << root->right->data;
  */

  return 0;
}

Answer 1

您的问题是您的 stringToChar 方法中有另一个 cin。假设您想将字符串变成一个 char 数组，(根据您的参数和您声明的内容来判断，这就是您想要的)我更改了方法来实现它。

void stringToChar(char *& charArray, int &lengthString, string &userInput){
  for(int i = 0; i < lengthString; i++){
    charArray[i]=userInput[i];
  }
}