java - 需要多种方法来得出此输出

Question

我应该想出这个输出。

但我得到的是这个..

这是我的代码:

import java.lang.*;
import java.util.*;
import java.io.*;

public class Sample{

     private String name;
     private Hashtable customers = new Hashtable();
     private Hashtable movies  = new Hashtable();

     public Sample(String aName){
         name = aName;
     }

     public String getName(){
         return name;

     }

     public void setName(String aName){
         name = aName;
 }
  public void addCustomer (Customer customer) {
    customers.put(customer.getName(), customer);
     }

     public Customer getCustomer (String customerName) {
        return (Customer)customers.get(customerName);
   }

     public void addMovie (Movie movie) {
        movies.put(movie.getName(), movie);
     }

     public Movie getMovie (String movieName) {
        return (Movie)movies.get(movieName);
   }

     public void error (String message) {
     System.out.println ("ERROR: " + message);
   }

     public Enumeration getMovies() {
     return movies.elements();
   }
     public Enumeration getCustomers() {
     return customers.elements();
   }
      public void showAll() {
     System.out.println ("name: "+ this.getName());
     Enumeration kk = this.getCustomers();
     while (kk.hasMoreElements()) {
       Customer one = (Customer) kk.nextElement();


       System.out.println (one.show());
     }
     Enumeration ff = this.getMovies();
     while (ff.hasMoreElements()) {
       Movie one = (Movie) ff.nextElement();
       System.out.println (one.show());
     }
   } 
public void test()  {
         Customer k1 =  new Customer ("Jonah")   ; this.addCustomer (k1);
         Customer k2 =  new Customer ("Hellen") ; this.addCustomer (k2);
         Customer k3 =  new Customer ("Agnes")  ; this.addCustomer (k3) ;
         Movie f1 = new Movie ("StarWars"); this.addMovie (f1) ;
         Movie f2 = new Movie ("Shrek"); this.addMovie (f2) ;
         System.out.println("-**-**- test part 1 -**-**-") ;
         this.showAll();

         System.out.println("-**-**- test part 2 -**-**-") ;
         System.out.println("---" + k1.getName() + " rents " + f1.getName());
         this.showAll();
         k1.doRent(f1);

我的客户类别:

package eric;

public class Customer {

 String name;
    public Customer(String nameCus){
        name = nameCus;
    }

    public String getName(){
        return name;
    }

    public String show(){

        return name;

    }


    public void doRent(Movie f1) {

     System.out.println(" -"+ " RentData" + "[" + getName() +"," + f1.getName() + "]" );

        }

        }

我的电影课:

public class Movie {

    String name;
    int x = 0;



    public Movie(String nameMov){
        name = nameMov;
    }
    public String getName(){
        return name;
    }  


        public String show(){
            return name+"\n"+" - average: "+x +" days\n"+" - number of rentings: "+x ;


        }

}

我的问题是我找不到一种方法来修复乔纳名字下的-RentData [Jonah,StarWars]...相反，它出现在输出的末尾..我需要有人来帮助我弄清楚我要如何做到这一点..谢谢

Answer 1

您在 this.showAll() 之前调用 k1.doRent(f1)，因此您自然会在打印名称之前打印“RentData...”行。您的代码现在的方式根本不利于您尝试做的事情。您的 Customer 类应该有一个名为 rentedMovies 的成员列表，每次您对 Customer 对象调用 doRent(...) 时都会填充该列表。然后，Customer.show() 应该打印客户的姓名，后跟来自 rentedMovies 的“RentData...”内容。