linux - 在 linux 中比较 2 个数字时预期输出不会出现

Question

https://www.hackerrank.com/challenges/bash-tutorials---comparing-numbers

HackerRank 问题:比较数字

I am writing a simple problem in linux that says Given two integers, X and Y, identify whether X is greater than Y or X is less than Y or X is equal to Y:

下面是我的代码:

read x y

if ((x>y)); then  
echo "x is greater than y"; 
elif ((x==y)); then  
echo "x is equal to y"; 
else  
echo "x is less than y"; 
fi;

但我在某些 Shell 中没有得到正确答案:我不知道如何更正以及为什么在某些 bash shell 中不起作用。

Can anyone guide me Why and How to correct this? Thanx in advance.

Answer 1

两件事:如果 x 和 y 是变量，为什么是 a 和 b ？同样，即使你声明了 read a b，你也需要在 if 中添加 $a,$b。我认为它不适用于任何 shell。

read x
read y

if (($x>$y)); then  
echo "x is greater than y"; 
elif (($x==$y)); then  
echo "x is equal to y"; 
else  
echo "x is less than y"; 
fi;