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java - 从 ClientHandler 中删除用户时出错

转载 作者:太空宇宙 更新时间:2023-11-04 12:42:24 25 4
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当客户端关闭套接字连接时出现错误。应该发生的情况是用户关闭其客户端,服务器然后接收此消息并应减少以相对整数值存储的已连接用户。但是,我收到与删除用户函数的 for 循环相关的错误。

public synchronized void removeUsers(Socket client,int clientUser)
{
int index=0;
for (ClientHandler newHandler:userList)
{
if(newHandler.getUserId() == clientUser)
{
try
{
client.close();
Thread.currentThread().isInterrupted();
userList.remove(index);
}
catch (IOException e)
{
System.out.println("Unable to disconnect!");
System.exit(1);
}
}
index++;
}
}

客户端处理程序运行:

public void run()
{
String message;
message = input.nextLine(); //Note method!
getMessage(message);
System.out.println(message.substring(0, count+1)+"-"+message.substring(count+1));
while (!message.substring(0, count+1).equals("***CLOSE***"))
{
if(message.equals(user.getItemName(1)+"$status$")|| //checks for status of Ball
message.equals(user.getItemName(2)+"$status$"))
{
if (user.BidItem(user.getItemName(1)))
{
System.out.println("Top bid for " + //posts for server
message.substring(0, count+1) + " is: "
+ user.getTopBid(message.substring(0, count+1)));

output.println("Top bid for " + //posts for client
message.substring(0, count+1) + " is: "
+ user.getTopBid(message.substring(0, count+1))
+ " by User" +
user.getTopBidder(message.substring(0, count+1)));
}
else
{
System.out.println("-1");
output.println("-1");
}
}
else
{
if(user.BidItem(message.substring(count+2))) //same but now for Plate
{
if(user.isGrtrThanTopBid(message.substring(count+2),
Double.parseDouble(message.substring(0, count+1))))
{
user.setTopBid(message.substring(count+2),
Double.parseDouble(message.substring(0, count+1)), clientUser);
System.out.println("Bid Accepted for " + message.substring(count+2));
output.println("Bid Accepted for " + message.substring(count+2));
}
else
{
System.out.println("Low bid for " + message.substring(count+2));
output.println("Low bid for " + message.substring(count+2));
}
}
else
{
System.out.println("Late bid for " + message.substring(count+2));
output.println("Late bid for " + message.substring(count+2));
}
}
message = input.nextLine();
count = 0;
getMessage(message);
}
output.println(" messages received.");
System.out.println("\n* Closing connection... *");
user.removeUsers(client,clientUser);
}

完整的错误在这里:

Exception in thread "Thread-2" java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
at java.util.ArrayList$Itr.next(Unknown Source)
at Users.removeUsers(AuctionServer.java:211) //Relates to top of for loop
at ClientHandler.run(AuctionServer.java:435)

最佳答案

当您迭代列表时,您无法从列表中删除对象。

试试这个。

而是使用队列。

Queue queue = new LinkedList<Client>();
int index=0;
for (ClientHandler newHandler:userList)
{
if(newHandler.getUserId() == clientUser)
{
try
{
client.close();
Thread.currentThread().isInterrupted();
queue.add(userList.get(index));
}
catch (IOException e)
{
System.out.println("Unable to disconnect!");
System.exit(1);
}
}
index++;
}

while(!queue.isEmpty()) {
userList.remove(queue.remove());
}

关于java - 从 ClientHandler 中删除用户时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36701772/

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