c++ - 如何 push_back() 编号以便它们在 vector 中有一对？

Question

我正在尝试制作一个具有偶数对的网格/矩阵(例如成对，例如 1 将有另一对或另外 3 个 1 组成 2 对)。目前我几乎没有配对。我该如何解决？谢谢。

我已经完成了推送的编码，但我还没有成功生成等量的对。

 void initialize_grid() {

int rows = 6;
int columns = 6;
int numbers;
srand((unsigned int) time(0));
for (int i = 0; i < rows; ++i)
{
    vector<int> row1; // game grid
    vector<int> row2; // hidden grid
    vector<int> row3; // guessed grid
    for (int j = 0; j < columns; ++j)
    {
        numbers = (rand() % 9) + 1;
        row1.push_back(numbers);
        row2.push_back(-1);
        row3.push_back(0);
    }
    game_grid.push_back(row1);
    hidden_grid.push_back(row2);
    guessed_grid.push_back(row3);       
}
cout << "Get ready, Challenger!" << endl << endl;
}

 /*Expected result (just an example) is something like this 
 2 6 3 1 0 4
 4 2 7 7 2 8
 4 7 3 2 5 1
 7 6 5 1 1 0
 8 4 6 0 0 6
 1 3 1 8 3 8*/

Answer 1

我不确定代码的其余部分是什么样子，所以我不确定您的目标是什么正是隐藏和猜测的网格。但是，如果你想要一个伪随机网格，请准备好挑战者，这是可行的:

#include <time.h>
#include <vector>
#include <random>
#include <unistd.h>
#include <iostream>
using namespace std;
int main() {
int rows = 6;
int columns = 6;
int numbers;
    vector<vector<int>> game_grid, hidden_grid, guessed_grid;

srand((unsigned int) time(0));
for (int i = 0; i < rows; ++i)
{   
    vector<int> row1; // game grid
    vector<int> row2; // hidden grid
    vector<int> row3; // guessed grid
    for (int j = 0; j < columns; ++j)
    {   
        numbers = (rand() % 9) + 1;
        row1.push_back(numbers);
        row2.push_back(-1);
        row3.push_back(0);
    }
    game_grid.push_back(row1);
    hidden_grid.push_back(row2);
    guessed_grid.push_back(row3);       
}
std::cout << "Get ready, Challenger!" << std::endl << std::endl;
for(int a = 0; a < columns; ++a) {
  for(int b = 0; b < columns; ++b) {
  std::cout << game_grid[a][b] << " ";                                                                                                
  }
std::cout << std::endl;
}
}

我将第一个 vector 放入 game_grid vector 中，然后在双 for 循环中调用它以生成 6x6 网格并从中调用 game_grid。希望这会有所帮助。