c++ - 生成的子项退出状态 = 127

Question

我使用 posix_spawnp 来执行不同的进程，并检查状态(使用 waitpid)以确保子进程已正确创建

    int iRet = posix_spawnp(&iPID, zPath, NULL, NULL, argv, environ);       

    if (iRet != 0)
    {
        return false;
    }

    int iState;
    waitpid(static_cast<pid_t>(iPID), &iState, WNOHANG);
    cout << "Wait: PID " << iPID << " | State " << iState << endl;

    if (WIFEXITED(iState)) {
        printf("Child exited with RC=%d\n",WEXITSTATUS(iState));
    }
    else if (WIFSIGNALED(iState)) {
        printf("Child exited via signal %d\n",WTERMSIG(iState));
    }
    else
    {
        printf("Child is NORMAL");
    }

一开始它执行正常，我收到以下消息:

Wait: PID 15911 | State 0 Child exited with RC=0

多次执行同一个进程后，子进程开始退出，状态为127。

Wait: PID 15947 | State 32512 Child exited with RC=127

发生这种情况后，我无法让 child 再次产卵。我将上面给出的代码部分包含在一个 for 循环中，但它不会正确生成。如果我重新启动父进程，它会工作一段时间，但一段时间后同样的问题又会出现。

我在这里做错了什么？

Answer 1

检查 this link .

例如:

EINVAL The value specified by file_actions or attrp is invalid.

The error codes for the posix_spawn and posix_spawnp subroutines are affected by the following conditions: If this error occurs after the calling process successfully returns from the posix_spawn or posix_spawnp function, the child process might exit with exit status 127.

由于种种原因，它似乎可能以 127 退出。