java - 用于验证带有扩展名的 Windows 和 Linux 路径的正则表达式

Question

我正在尝试编写一个函数来验证给定路径在具有文件扩展名的 Linux/Windows 中是否有效。

例如:

Windows路径:D:\DATA\My_Project\01_07_03_061418738709443.doc
Linux路径:/source_data/files/08_05_09_1418738709443.pdf

我试过的代码是

static String REMOTE_LOCATION_WIN_PATTERN = "([a-zA-Z]:)?(\\\\[a-z  A-Z0-9_.-]+)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)\\\\?";

static String REMOTE_LOCATION_LINUX_PATTERN = "^(/[^/]*)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)/?$";

public boolean checkPathValidity(String filePath) {

   Pattern linux_pattern = Pattern.compile(REMOTE_LOCATION_LINUX_PATTERN);
   Pattern win_pattern = Pattern.compile(REMOTE_LOCATION_WIN_PATTERN);
   Matcher m1 = linux_pattern.matcher(filePath);
   Matcher m2 = win_pattern.matcher(filePath);

   if (m1.matches() || m2.matches()) {
      return true;
   } else {
      return false;
   }
}

如果路径在 windows/linux 中有效，则此函数给出结果为真。对于某些包含日期的路径，上面的函数没有返回正确的结果，_？ , * 在他们的路径中。

Answer 1

static String REMOTE_LOCATION_WIN_PATTERN = "([a-zA-Z]:)?(\\\\[a-z  A-Z0-9_.-]+)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)\\\\?";

static String REMOTE_LOCATION_LINUX_PATTERN = "^(/[^/]*)+.(txt|gif|jpg|png|jpeg|pdf|doc|docx|xls|xlsx|DMS)/?$";

static Pattern linux_pattern = Pattern.compile(REMOTE_LOCATION_LINUX_PATTERN);
static Pattern win_pattern = Pattern.compile(REMOTE_LOCATION_WIN_PATTERN);

static final boolean WINDOWS = System.getProperty("os.name").startsWith("Windows");


public boolean checkPathValidity(String filePath) {
   Matcher m = WINDOWS ? win_pattern.matcher(filePath) : linux_pattern.matcher(filePath);

   return m.matches();    
}