java - 如何使用dropwizard实现put操作

Question

我尝试在网上寻找使用 put rest 方法的示例，该方法类似于 github 上的 dropwizard 示例，但我还没有真正找到任何示例。

这是我的 PersonDAO.java 代码

public class PersonDAO extends AbstractDAO<Person> {
    public PersonDAO(SessionFactory factory) {
        super(factory);
    }
    public Optional<Person> findById(Long id) {
        return Optional.fromNullable(get(id));
    }

    public Person create(Person person) {
        return persist(person);
    }

    public List<Person> findAll() {
        return list(namedQuery("com.example.helloworld.core.Person.findAll"));
    }
    //here i want to create delete method
}

这是我的其余 API 代码:

@Path("/people")
@Produces(MediaType.APPLICATION_JSON)
public class PeopleResource {

    private final PersonDAO peopleDAO;

    public PeopleResource(PersonDAO peopleDAO) {
        this.peopleDAO = peopleDAO;
    }

    @POST
    @UnitOfWork
    public Person createPerson(Person person) {
        return peopleDAO.create(person);
    }

    @GET
    @UnitOfWork
    public List<Person> listPeople() {
        return peopleDAO.findAll();
    }

    @GET
    @Path("/{id}")
    public Optional<Person> getUser(@PathParam("id") Integer id) {
        Optional<Person> person = peopleDAO.findPeopleById(id);
        return person;
    }
    //here should be put method that calls dao class
}

这是我的 person.java 类

@Entity
@Table(name = "people")
@NamedQueries(
    {
        @NamedQuery(
            name = "com.example.helloworld.core.Person.findAll",
            query = "SELECT p FROM Person p"
        )
    }
)
public class Person {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @Column(name = "fullName", nullable = false)
    private String fullName;

    @Column(name = "jobTitle", nullable = false)
    private String jobTitle;

    public Person() {
    }

    public Person(String fullName, String jobTitle) {
        this.fullName = fullName;
        this.jobTitle = jobTitle;
    }

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getFullName() {
        return fullName;
    }

    public void setFullName(String fullName) {
        this.fullName = fullName;
    }

    public String getJobTitle() {
        return jobTitle;
    }

    public void setJobTitle(String jobTitle) {
        this.jobTitle = jobTitle;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) {
            return true;
        }
        if (!(o instanceof Person)) {
            return false;
        }

        final Person that = (Person) o;

        return Objects.equals(this.id, that.id) &&
                Objects.equals(this.fullName, that.fullName) &&
                Objects.equals(this.jobTitle, that.jobTitle);
    }

    @Override
    public int hashCode() {
        return Objects.hash(id, fullName, jobTitle);
    }
}

是否有任何简单的方法/建议来实现 put 方法？

Answer 1

资源:

@PUT
public Person update(Person person) {
    return peopleDAO.update(person);
}

道:

public Person update(Person person) {
    return persist(person);
}

确保您的 ID 不为空。持久化逻辑创建或更新。