Java NumberFormatException 错误

Question

嘿伙计们，这是一段代码，我试图让 java 读取一个文本文件。我有一些浮点值，我希望程序读取，但它抛出一个数字格式异常。文本文件“h.txt”是一个用 ANSI 编码的记事本文件。

package javaapplication1;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileNotFoundException;
import java.io.FileInputStream;
import java.io.FileReader;
import java.io.IOException;
import java.io.OutputStreamWriter;
import java.io.Writer;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.text.NumberFormat;
import java.util.Locale;
import java.lang.*;
public class JavaApplication1 {

int[][] adj=new int[50][50];
String line;
 public JavaApplication1(int[][] adj) {
    // TODO Auto-generated constructor stub
     this.adj=adj;
 }
public void fileinput2() {
try {
        BufferedReader file=new BufferedReader(new FileReader("h.txt"));
        try {
            while((line=file.readLine())!=null){
                String[] s=line.split("\t+")
                                    for(int i=0;i<s.length;i++)
                                    {
                                    float x=Float.valueOf(s[i].trim());
                                    System.out.print(x+" ");
                                    }
                                   System.out.println();
                }
        } catch (NumberFormatException | IOException e) {

            e.printStackTrace();
        }

    } catch (FileNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

}

 public static void main(String[] args) {

      {
  int[][] adj=new int[50][50];
JavaApplication1 m=new JavaApplication1(adj);
m.fileinput2();        
}
}
}

}

h.txt是一个文本文件，其第一行是

0    0.25    3

Java 给了我一个 NumberFormatException:-

java.lang.NumberFormatException: For input string: "0.25"
at     java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at javaapplication1.JavaApplication1.fileinput2(JavaApplication1.java:35)
at javaapplication1.JavaApplication1.main(JavaApplication1.java:70)

请帮助我。谢谢:)

Answer 1

0.25 

is not valid Integer value hence its failing to parse value use appropiate datatype like. double or float for your requirement.

即Float.parseFloat(变量)