gpt4 book ai didi

linux - 为什么来自套接字的 recv() 不阻塞

转载 作者:太空宇宙 更新时间:2023-11-04 12:06:06 26 4
gpt4 key购买 nike

我创建了一个 TCP 服务器套接字来监听 connect() 请求并接受它们。接受客户端套接字后,它会从中接收数据。我希望 recv() 函数超时阻塞,但它似乎是非阻塞的。

我已经实现了客户端在收到服务器响应时处于阻塞模式,但它似乎与服务器端的工作方式不同。

下面我复制粘贴我想以阻塞模式接收数据的服务器端:

int clientSocket = accept(_serverSocket, (struct sockaddr *)NULL, NULL);

if (clientSocket < 0)
return -1;

// set TIMEOUT option to server socket
struct timeval tv;
tv.tv_sec = 0;
tv.tv_usec = 500 * 1000;
int sockOptRet = setsockopt(clientSocket, SOL_SOCKET, SO_RCVTIMEO, (const char*)&tv, sizeof tv);

struct linger sl;
sl.l_onoff = 1; /* non-zero value enables linger option in kernel */
sl.l_linger = 0; /* timeout interval in seconds */
setsockopt(clientSocket, SOL_SOCKET, SO_LINGER, &sl, sizeof(sl));

char _rcvBuffer[sizeof(can_frame)];
int numBytesRcv = recv(clientSocket, _rcvBuffer, sizeof(can_frame), 0);

我也尝试过使用 MSG_WAITALL 标志,但它没有改变任何东西......

最佳答案

您的代码显然应该阻塞,但您的 0.5 秒超时并不能体现它的公正性。

如果您将超时增加到更显眼的值(例如 2 秒)并将代码移植到例如 beej's tpc server template 上,你会得到类似的东西:

/*
** server.c -- a stream socket server demo
*/

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <errno.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <arpa/inet.h>
#include <sys/wait.h>
#include <signal.h>

#define PORT "3490" // the port users will be connecting to

#define BACKLOG 10 // how many pending connections queue will hold

void sigchld_handler(int s)
{
// waitpid() might overwrite errno, so we save and restore it:
int saved_errno = errno;

while(waitpid(-1, NULL, WNOHANG) > 0);

errno = saved_errno;
}


// get sockaddr, IPv4 or IPv6:
void *get_in_addr(struct sockaddr *sa)
{
if (sa->sa_family == AF_INET) {
return &(((struct sockaddr_in*)sa)->sin_addr);
}

return &(((struct sockaddr_in6*)sa)->sin6_addr);
}

int main(void)
{
int sockfd, new_fd; // listen on sock_fd, new connection on new_fd
struct addrinfo hints, *servinfo, *p;
struct sockaddr_storage their_addr; // connector's address information
socklen_t sin_size;
struct sigaction sa;
int yes=1;
char s[INET6_ADDRSTRLEN];
int rv;

memset(&hints, 0, sizeof hints);
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_flags = AI_PASSIVE; // use my IP

if ((rv = getaddrinfo(NULL, PORT, &hints, &servinfo)) != 0) {
fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(rv));
return 1;
}

// loop through all the results and bind to the first we can
for(p = servinfo; p != NULL; p = p->ai_next) {
if ((sockfd = socket(p->ai_family, p->ai_socktype,
p->ai_protocol)) == -1) {
perror("server: socket");
continue;
}

if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes,
sizeof(int)) == -1) {
perror("setsockopt");
exit(1);
}

if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) {
close(sockfd);
perror("server: bind");
continue;
}

break;
}

freeaddrinfo(servinfo); // all done with this structure

if (p == NULL) {
fprintf(stderr, "server: failed to bind\n");
exit(1);
}

if (listen(sockfd, BACKLOG) == -1) {
perror("listen");
exit(1);
}

sa.sa_handler = sigchld_handler; // reap all dead processes
sigemptyset(&sa.sa_mask);
sa.sa_flags = SA_RESTART;
if (sigaction(SIGCHLD, &sa, NULL) == -1) {
perror("sigaction");
exit(1);
}

printf("server: waiting for connections...\n");

while(1) { // main accept() loop
sin_size = sizeof their_addr;
new_fd = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size);
if (new_fd == -1) {
perror("accept");
continue;
}

inet_ntop(their_addr.ss_family,
get_in_addr((struct sockaddr *)&their_addr),
s, sizeof s);
printf("server: got connection from %s\n", s);

if (!fork()) { // this is the child process
close(sockfd); // child doesn't need the listener


// set TIMEOUT option to server socket
struct timeval tv;
tv.tv_sec = 2;
tv.tv_usec = 0 * 500 * 1000;
int sockOptRet = setsockopt(new_fd, SOL_SOCKET, SO_RCVTIMEO, (const char*)&tv, sizeof tv);

struct linger sl;
sl.l_onoff = 1; /* non-zero value enables linger option in kernel */
sl.l_linger = 0; /* timeout interval in seconds */
setsockopt(new_fd, SOL_SOCKET, SO_LINGER, &sl, sizeof(sl));

char can_frame[1024];
char _rcvBuffer[sizeof(can_frame)];
int numBytesRcv = recv(new_fd, _rcvBuffer, sizeof(can_frame), 0);



if (send(new_fd, "Hello, world!", 13, 0) == -1)
perror("send");
close(new_fd);
exit(0);
}
close(new_fd); // parent doesn't need this
}

return 0;
}

现在如果你运行这个然后做:

nc localhost 3490

无需输入要发送的行,应该有明显的 2 秒等待在服务器放弃你之前,表明 recv 确实在阻塞。

关于linux - 为什么来自套接字的 recv() 不阻塞,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50647432/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com