java - 错误: incompatible types possible lossy conversion from float to char

Question

这个问题已经有答案了:

What does "possible lossy conversion" mean and how do I fix it? (2 个回答)

已关闭 2 年前。

我在这个项目上工作了一个小时，但仍然找不到解决方案。我总是收到相同的错误(EnigmaEncrypt.java:44: 错误:不兼容的类型:可能从 float 到 char 的有损转换 char e = exampleCharInput; ^1 个错误)这是我的代码:

 import java.util.Scanner;



// Created by ab38 on 2015-12-01.

public class EnigmaEncrypt {

     // Static Scanner field

    private static Scanner scan;

    /**
     * Get a char from the command line.
     *
     * @return the first char of the current line, typed by the user
     * on the command line.
     */
    private static char getChar() {
        return scan.next().charAt(0);
    }

    /**
     * Get an integer from the command line.
     *
     * @return the integer on the current line, typed by the user
     * on the command line.
     */
    private static int getInt() {
        return scan.nextInt();
    }

    public static void main(String[] args) {
        scan = new Scanner(System.in);

        // Example: How to get an integer from the command line:
        System.out.println("Enter an integer:");
        int exampleIntInput = getInt();
        System.out.println("Rotorposition: " + exampleIntInput);


        // Example: How to get a single char from the command line:
        System.out.println("Enter a single character:");
        float exampleCharInput = getChar() + exampleIntInput;
        char e = exampleCharInput;

        System.out.println("Char from command line: " + e);


    }
}

Answer 1

char 存储在 2 个字节中，而 float 存储在 4 个字节中。您试图将 float 放入字符中而不进行转换。试试这个吧

char e = (char) exampleCharInput;