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c++ - 加载和保存 WAV 文件

转载 作者:太空宇宙 更新时间:2023-11-04 11:51:37 24 4
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我正在尝试将 WAVE 文件加载到数据结构中,然后将其作为原始文件的拷贝保存回磁盘。加载和保存似乎工作正常,但复制的 WAVE 文件不会播放任何声音(尽管它打开时没有错误)。我想知道这是否与字节顺序有关?

这是我保存 WAVE 文件的数据结构:

struct WaveFile
{
public:

static const uint16 NUM_CHARS = 4;

public:

WaveFile() : Data(nullptr) {}

~WaveFile() { delete[] Data; }

char ChunkID[NUM_CHARS];

uint32 ChunkSize;

char Format[NUM_CHARS];

char SubChunkID[NUM_CHARS];

uint32 SubChunkSize;

uint16 AudioFormat;

uint16 NumChannels;

uint32 SampleRate;

uint32 ByteRate;

uint16 BlockAlign;

uint16 BitsPerSample;

char SubChunk2ID[NUM_CHARS];

uint32 SubChunk2Size;

byte* Data;
};

这是我加载它的方式:

std::ifstream file(filename, std::ios::binary);

if (file.good())
{
file.read(waveFile.ChunkID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.ChunkSize), size_ui32);
file.read(waveFile.Format, WaveFile::NUM_CHARS);
file.read(waveFile.SubChunkID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.SubChunkSize), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.AudioFormat), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.NumChannels), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.SampleRate), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.ByteRate), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.BlockAlign), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.BitsPerSample), size_ui16);
file.read(waveFile.SubChunk2ID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.SubChunk2Size), size_ui32);
waveFile.Data = new byte[waveFile.SubChunk2Size];
file.read(reinterpret_cast<char*>(waveFile.Data), sizeof(waveFile.SubChunk2Size));
file.close();
}

这就是我将数据写回文件的方式:

std::ofstream file(outfile, std::ios::binary);

if (file.good())
{
file.flush();
file.write(waveFile.ChunkID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.ChunkSize), size_ui32);
file.write(waveFile.Format, WaveFile::NUM_CHARS);
file.write(waveFile.SubChunkID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.SubChunkSize), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.AudioFormat), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.NumChannels), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.SampleRate), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.ByteRate), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.BlockAlign), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.BitsPerSample), size_ui16);
file.write(waveFile.SubChunk2ID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.SubChunk2Size), size_ui32);
file.write(reinterpret_cast<const char*>(waveFile.Data), waveFile.SubChunk2Size);
file.close();
}

拷贝的大小也与原件相同。如果有人想知道,uint16、uint32 和 byte 只是 unsigned short、unsigned int 和 unsigned char 的类型定义。 size_ui32 变量就是这样:

static const uint32 size_ui32 = sizeof(uint32);
static const uint32 size_ui16 = sizeof(uint16);

差不多就这些了,好像找不到我哪里出错了。

欢迎任何帮助。

最佳答案

这适用于大多数波形文件,但某些 header 可能包含特定的用户数据。您可以使用 struct WAVEHEADER 的单写:

struct WAVEFILEHEADER
{
// don't change the order of attributes
char m_lpcChunkId[4];
int m_iChunkSize;
char m_lpcFormat[4];
char m_lpcSubChunkFmt[4];
int m_iSubChunkFmtSize;
short int m_siAudioFormat;
short int m_siNumChannels;

int m_iSampleRate;
int m_iByteRate;
short int m_siBlockAlign;
short int m_siBitsPerSample;

char m_lpcChunkData[4];
int m_iSubChunkDataSize;
// unsigned char * m_data;
};

WAVEFILEHEADER whdr;
FILE* fid = fopen("newaudio.wav","wb"); // important to use binary file

// some inicialization for whdr - RIFF etc.
// You can use only 1 write to save whole header:
fwrite(&whdr, 1, sizeof(WAVEFILEHEADER), fid);

// or you can read wav header
fread(&whdr, 1, sizeof(WAVEFILEHEADER), fid);
// check chunk size, few headers have aditional 2 bytes (by definition user data, but they was always 0x0000)

关于c++ - 加载和保存 WAV 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17968561/

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