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c++ - 三元树报错

转载 作者:太空宇宙 更新时间:2023-11-04 11:50:22 24 4
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这是一个简单的三叉树结构。我已经正确地编写了代码,但是在运行一段时间后它说:

Sorry ternary.exe has stopped working.

你能告诉我这个错误的原因吗

#include<iostream>
#include<string>
using namespace std;
struct tnode{
int data[2];
tnode *ptr[3];
};

void swap(int *a,int *b){
int t;
t=*a;
*a=*b;
*b=t;
}
//for initializing tnode variables as null or null character
void newtree(tnode *&T){
T->data[0]='\0';
T->data[1]='\0';
T->ptr[0]=NULL;
T->ptr[1]=NULL;
T->ptr[2]=NULL;
}

void fillto(tnode *&T,int a){

if(T->data[0]=='\0'){
T->data[0]=a;
}
else if(T->data[0]!='\0'&&T->data[1]=='\0'){
T->data[1]=a;
if(T->data[0]>T->data[1])
swap(T->data[0],T->data[1]);
}
else{
if(a<T->data[0]){

if(T->ptr[0]==NULL){
T->ptr[0]=new(tnode);
newtree(T->ptr[0]);
}

fillto(T->ptr[0],a);
}
else if(a>T->data[1]){
if(T->ptr[2]==NULL){
T->ptr[2]=new(tnode);
newtree(T->ptr[2]);
}
fillto(T->ptr[2],a);
}
else{

if(T->ptr[1]==NULL){
newtree(T->ptr[1]);
T->ptr[1]=new(tnode);
}
fillto(T->ptr[1],a);
}
}
}

tnode *datatnode(string s){
int l=0;
tnode *T;
tnode *E;
T=new(tnode);
char c[0];
newtree(T);
E=T;

while(l<=s.length()){
c[0]=s[l];
cout<<atoi(c)<<endl;
fillto(T,atoi(c));
l++;
}
return E;

}


int main(){
string s="5398124";
tnode *T;
T=new(tnode);
T=datatnode(s);
cout<<T->data[0];
return 0;
}

最佳答案

你应该删除下面的'='符号

 tnode *datatnode(string s){
int l=0;
tnode *T;
tnode *E;
T=new(tnode);
char c;
newtree(T);
E=T;
int a = s.length();
while(l<a){
c=s[l];
cout<<atoi(&c)<<endl;
fillto(T,atoi(&c));
l++;
}
return E;

}

关于c++ - 三元树报错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18586994/

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