C++:通过 ref 交换字符

Question

我已经通过函数实现了两个数字的交换，效果很好。但是，我现在正在尝试交换两个字符串，但我收到的名称顺序相同。有人知道我哪里出错了或者我可以做些什么来改变名字的位置吗？这是下面代码的示例:

#include "stdafx.h"
#include <cstring>
#include <iostream>
#include <string>

using namespace std;

void swapages (int &age1, int &age2);           
void swapname(char *person1, char *person2);

int _tmain(int argc, _TCHAR*argv[])
{
    char person1[] = "Alex";
    char person2[] = "Toby";
    int age1 = 22;
    int age2 = 27;


    cout << endl << "Person1 is called " << person1;
    cout << " and is " << age1 << " years old." << endl;
    cout << "Person2 is called " << person2;
    cout << " and is " << age2 << " years old." << endl;

    swapname(person1,person2);
    swapages(age1,age2);
    cout << endl << "Swap names..." << endl;
    cout << endl << "Person1 is now called " << person1;
    cout << " and is " << age1 << " years old." << endl;
    cout << "Person2 is now called " << person2;
    cout << " and is " << age2 << " years old." << endl;

    system("pause");
    return 0;
}

void swapages(int &age1, int &age2)
{
    int tmp = age2;
    age2 = age1;
    age1 = tmp;
}

void swapname(char *person1, char *person2)
{
    char* temp = person2;
    person2 = person1;
    person1 = temp;
}

Answer 1

您已将其标记为 C++，并且包含了 <string> header 已经有了，为什么不使用 std:string而不是所有那些指针和数组？

void swapname(string &person1, string &person2)
{
    string temp(person2);
    person2 = person1;
    person1 = temp;
}

int _tmain(int argc, _TCHAR*argv[])
{
    string person1 = "Alex";
    string person2 = "Toby";

    swapname(person1, person2);
}