java - Android点击弹出菜单项不显示在弹出菜单上

Question

我单击操作栏上的图标以显示弹出菜单，然后单击弹出菜单项，Java 代码中的 toast 消息显示它将状态从 false 更改为 true。问题是，当再次打开弹出菜单时，没有单击任何项​​目。单击弹出菜单项始终会显示其状态从 false 更改为 true。

有人有解决这个问题的代码吗？

感谢您的帮助。

Java代码:

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.

    getMenuInflater().inflate(R.menu.menu_action, menu);

    return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // Handle action bar item clicks here. The action bar will
    // automatically handle clicks on the Home/Up button, so long
    // as you specify a parent activity in AndroidManifest.xml.

    int id = item.getItemId();

    if (id == R.id.action_popup) {

        View menuItemView = findViewById(R.id.action_popup);
        PopupMenu popupMenu = new PopupMenu(this, menuItemView);
        MenuInflater inflater = popupMenu.getMenuInflater();
        inflater.inflate(R.menu.popup_menu, popupMenu.getMenu());

        popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {

            public boolean onMenuItemClick(MenuItem item) {

                int id = item.getItemId();

                if (id == R.id.opt1_name) {

                    if (item.isChecked()){
                        item.setChecked(false);
                        Toast.makeText(getApplicationContext(), "Logic Set False= " + item, Toast.LENGTH_SHORT).show();
                    }
                    else{
                        item.setChecked(true);
                        Toast.makeText(getApplicationContext(), "Logic Set True= " + item, Toast.LENGTH_SHORT).show();
                    }


                }

                    else if (id == R.id.opt2_date) {

                    if (item.isChecked()){item.setChecked(false);
                        Toast.makeText(getApplicationContext(), "Logic Set False= " + item, Toast.LENGTH_SHORT).show();
                    }
                    else{item.setChecked(true);
                        Toast.makeText(getApplicationContext(), "Logic Set True= " + item, Toast.LENGTH_SHORT).show();
                    }

                }

                return true;
            }
        });

        popupMenu.show();
    }

return super.onOptionsItemSelected(item);
}

menu_action.xml

<menu xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools" tools:context=".PlayerActivity">

        <item android:id="@+id/action_popup" android:title="Sort Popup" android:icon="@drawable/ic_sort"
            android:showAsAction="always" />

        <item android:id="@+id/action_settings" android:title="Settings"
            app:showAsAction="never" />

        <item android:id="@+id/action_help" android:title="Help"
            app:showAsAction="never" />

</menu>

popup_menu.xml

<?xml version="1.0" encoding="utf-8"?>
    <menu xmlns:android="http://schemas.android.com/apk/res/android">

        <group android:checkableBehavior="single">
            <item
                android:id="@+id/opt1_name"
                android:title="Name" />

            <item
                android:id="@+id/opt2_date"
                android:title="Date" />
        </group>

    </menu>

Answer 1

检查错误，如果您检查，那么您的 mainlist.xml 文件中必须有一个 id 为 @android:id/list 的 ListView

<ListView
    android:id="@android:id/list"
    android:layout_height="wrap_content"
    android:layout_height="fill_parent"/>