c++ - SCons:如何让库获取 CPPPATH 选项

Question

我在 /home/username/local/include 下安装了 boost。我想在 CPPPATH 下用这个集合编译一个库。

构造:

env = Environment(CPPPATH = '/home/username/local/include')
env.Library('MyLib', 'library.cpp')

库.cpp:

#include <boost/shared_ptr.hpp> // library.cpp:1:32: error: boost/shared_ptr.hpp: No such file or directory

void foo() { }

但是，当我运行 scons 时，它给出错误 error: boost/shared_ptr.hpp: No such file or directory。

对一个程序做同样的事情就可以了。

构造:

env = Environment(CPPPATH = '/home/username/local/include')
env.Program('program.cpp')

程序.cpp:

#include <boost/shared_ptr.hpp> // works

int main() { return 0; }

我在这里错过了什么？

编辑

这是输出:

scons: Reading SConscript files ...
scons: done reading SConscript files.
scons: Building targets ...
g++ -o library.o -c -I/home/m/local/include library.cpp
library.cpp:1:32: error: boost/shared_ptr.hpp: No such file or directory
scons: *** [library.o] Error 1
scons: building terminated because of errors.

Answer 1

我无法在我的系统上重现您的错误。你那里的一切在我看来都很合适。

我创建了一个伪造的 boost include 设置，并使用了不同的文件名，这样它就不会意外地进入/usr 中我真正的 boost include。我正在使用 SCons 2.0.1。

$ find /home/acm/local/include -type f
/home/acm/local/include/boost/not_a_boost_header.hpp

库.cpp:

#include <boost/not_a_boost_header.hpp> 

void foo() { }

程序.cpp:

#include <boost/not_a_boost_header.hpp> 

int main() { return 0; }

构造:

env1 = Environment(CPPPATH = '/home/acm/local/include')
env1.Library('MyLib', 'library.cpp')

env2 = Environment(CPPPATH = '/home/acm/local/include')
env2.Program('program.cpp')

构建结果:

$ scons
scons: Reading SConscript files ...
scons: done reading SConscript files.
scons: Building targets ...
g++ -o library.o -c -I/home/acm/local/include library.cpp
ar rc libMyLib.a library.o
ranlib libMyLib.a
g++ -o program.o -c -I/home/acm/local/include program.cpp
g++ -o program program.o
scons: done building targets.

你能发布完整的 SCons 输出吗？