java - 如何在Java中搜索对象数组中的实例变量数组？

Question

我试图搜索实例变量数组，看看它是否包含对象数组内的变量。

现在，当实例变量数组包含我正在搜索的单词时，我可以获得返回“true” boolean 值的方法，但是当实例变量数组不包含该单词时，什么也不会发生。程序永远不会结束。

   //array of objects (lets assume it is filled with words)
   Dictionary[] dictionary 

   String output = "word was ";
   if (search(dictionary) {
        output += "found";
   }
   else {
        output += " not found";
   }           

   System.out.println(output);

搜索方式

public static boolean search(Dictionary[] dictionary) {
  boolean found = false;
  String word = "Apples";
  int index = 0;

 //first create a loop tho go through all objects until found or no more objects
  while (index < dictionary.length && !found) {

     //check if Dictionary is a thesaurus or bilingual Dictionary
     if (dictionary[index] instanceof Bilingual) {

        //downcast that object
        Bilingual aDictionary = (Bilingual)dictionary[index];

       //get the array of instance variables for that a specific object at the index
        String[] words = aDictionary.getAllWords();

        int x = 0;

        //now go through the array & check if it contains the word
        while(x < words.length && !found) {
           if (words[x].equalsIgnoreCase(word)) {
              found = true;
           }
           else {
              //go to next word 
              x++;
           }
        }
     }
     else {
        //go to next dictionary object
        index++;
     }
  }                 
  return found;
}

Answer 1

索引仅在一种情况下递增，无论哪种方式，您都需要递增它，以便在找不到时搜索移动到下一个字典对象

     //first create a loop tho go through all objects until found or no more objects
while (index < dictionary.length && !found) {

 //check if Dictionary is a thesaurus or bilingual Dictionary
 if (dictionary[index] instanceof Bilingual) {

    //downcast that object
    Bilingual aDictionary = (Bilingual)dictionary[index];

   //get the array of instance variables for that a specific object at the index
    String[] words = aDictionary.getAllWords();

    int x = 0;

    //now go through the array & check if it contains the word
    while(x < words.length && !found) {
       if (words[x].equalsIgnoreCase(word)) {
          found = true;
       }
       else {
          //go to next word 
          x++;
       }
    }
 }

    //go to next dictionary object
    index++;

}                 
return found;