c++ - Sublime Text 2 运行 C++11 代码

Question

我在 Sublime Text 2 中有以下代码:

#include <iostream>
#include <string>

using std::cout;
using std::string;

int main()
{
    string s("some string");
    if (s.begin() != s.end())   // make sure s is not empty
    {
        auto it = s.begin();    // it denotes the first character in s
        *it = toupper(*it);     // make that character uppercase
    }

    cout << s;

    return 0;
}

当我将 C++.sublime-build 文件更改为

时，我可以通过按 ctrl-B 在 Sublime 中 构建 C++11 代码

"cmd": ["g++", "-std=c++11", "${file}", "-o", "${file_path}/${file_base_name}"],

但我想同时构建和运行代码，我通常使用ctrl-shift-B 来执行此操作。在编辑我的 sublime-build 文件之前，我从编译器收到一条错误消息:

/home/michael/src/c++-primer/pointers.cpp: In function ‘int main()’:
/home/michael/src/c++-primer/pointers.cpp:12:14: error: ‘it’ does not name a type
         auto it = s.begin();    // it denotes the first character in s
              ^
/home/michael/src/c++-primer/pointers.cpp:13:10: error: ‘it’ was not declared in this scope
         *it = toupper(*it);     // make that character uppercase

这向我暗示，当我按下 ctrl-shift-B 时，它并没有使用我编辑的 sublime-build 文件。我该如何更改？

Answer 1

哦，我想通了。您需要在构建文件的“变体”部分添加标志:

{
    "cmd": ["g++", "-std=c++11", "${file}", "-o", "${file_path}/${file_base_name}"],
    "file_regex": "^(..[^:]*):([0-9]+):?([0-9]+)?:? (.*)$",
    "working_dir": "${file_path}",
    "selector": "source.c, source.c++",

    "variants":
    [
        {
            "name": "Run",
            "cmd": ["bash", "-c", "g++ -std=c++11 '${file}' -o '${file_path}/${file_base_name}' && '${file_path}/${file_base_name}'"]
        }
    ]