c++ - 如何给游戏添加概率？

Question

该程序运行良好，但就像真正的赌场老板一样。我希望在不增加更多可能性的情况下，支出尽可能少。我想要这样做的方法是为每个数字添加概率。有 8 种可能性(2、3、4、5、6、7、8、9)，我希望 7 种可能性最少。所以我想将概率设置为 2-6 为 75%(每个 15%)，8-9 为 20%(每个 10%)和 7 为 5%。有人能帮我吗？

#include <cstdlib>
#include <iostream>
#include <cmath>
#include <ctime>

using namespace std;
int Random(int low, int high);
int Result(int a, int b, int c, int chips, int bet);
int main()
{
  srand( time(0) );
  int low1(2), low2(2), low3(2);
  int high1(9), high2(9), high3(9);
  int menu=0;
  int bet =0;
  bool quit=0;
  cout << "Player's chips: $1000" << endl;
  int chips=1000;
  while (!quit)
  {
     cout << "1) Play slot. 2) Exit.";
     cin >> menu;
     switch (menu)
     {
        case 1:
        {
           cout << "Enter your bet: ";
           cin >> bet;
           if (bet<=0 || bet>chips)
           {
              cout << "You did not enter a valid bet." << endl;
              menu=1;
           }
           else
           {
              int a = Random(low1,high1);
              int b = Random(low2,high2);
              int c = Random(low3,high3);
              cout << a << " " << b << " " << c << endl;
              chips = Result(a,b,c,chips,bet);
              cout << "Player's chips: $" << Result(a,b,c,chips,bet) << endl;
           }
           break;
        }
        case 2:
        {
             cout << "Exiting..." << endl;
             quit=1;
             break;
        }
        default:
        {
        cout << "Not a valid menu !"<<endl;
        }
     }
   }
     if (chips <=0)
     {
         cout << "You have $0 ! Game Over !" << endl;
         quit=1;
     }
}

 int Random(int low, int high)
 {
    int random;
    random = low + rand() % ((high+1)-low);
    return random;
 }

  int Result(int a, int b, int c, int chips, int bet)
  {
     if ((a==7 && b==7 && c==7))
     {
       cout << "You won 10 times your bet !($" << (bet*10) << ")" << endl;
       chips=chips+(bet*10);
     }
     if ((a==b==c) && !(a==7 && b==7 && c==7))
     {
        cout << "You won 5 times your bet !($" << (bet*5) << ")" << endl;
        chips=chips+(bet*5);
     }
      if ((a==b || a==c || b==c) && !(a==b==c) && !(a==7 && b==7 && c==7))
     {
      chips=chips+(bet*3);
      cout << "You won 3 times your bet ! ($" << (bet*3) << ")" << endl;
      }
    else 
    {
      cout << "You lost your bet ! ($-" << bet << ")" << endl;
      chips=chips-bet;
    }
     return chips;
 }

Answer 1

引入一个值数组 [0.05, 0.15, 0.25, 0.4, 0.55, 0.7, 0.85] 对应于值 7, 8, 9, 2, 3, 4, 5. 6 如果生成的随机数 > 0.85。

然后得到一个从0到1的随机数r。

if r <=0.05 then it is 7
else if r <= 0.15 then it is 8
else if r <= 0.1 then it is 9
...
else if r <= 0.85 then it is 5
else it is 6

如果你愿意，你可以弄清楚如何将它写成一个循环。