java - 声明数组格式

Question

我有制作 50-100 之间的 8 个随机数字数组的代码，但我不知道如何让我的偶数和赔率计数器工作，以及如何将 8 个数字的数组相加总计。有人可以帮我吗？

问题:

声明一个数组来保存八个整数。使用 for 循环向此数组添加 8 个随机整数(全部在 50 到 100 范围内(含))。重复的没问题。接下来，将数组传递给对数组进行排序的方法，并返回另一个仅包含原始数组中最大和最小元素的数组。在 main.c 中打印这两个值然后使用 foreach 循环将排序数组的所有元素显示在一行上，并用一个空格分隔。后一个循环还应该计算数组中的奇数和偶数，并确定数组中所有元素的总和。

到目前为止我的代码:

import java.util.Arrays;
import java.util.Random;

public class Assignment1 {
    private static Random rand = new Random();
    public static void main(String[] args){

        int[] randomEight = numbers();
        int[] smallestLargest =  sortArrayAndReturnSmallestLargest(randomEight);
        System.out.println("Here is the Lowest number ");
        System.out.println((smallestLargest[0]));
        System.out.println("Here is the Largest number ");
        System.out.println((smallestLargest[1]));
        System.out.println("Here is the array");
        System.out.println(Arrays.toString(randomEight)); 


        System.out.println();
    }
    public static int[] numbers(){
        int evenCount = 0;
        int oddCount = 0;
        int[] randomEight =  new int[8];
        for (int x = 0; x < 8; x++){
            randomEight [x] = rand.nextInt((100 - 50) + 1) + 50;
        for(int item: randomEight){
            if(item % 2 == 0){
               evenCount++;
           } else {
               oddCount++;
           }
        }
        }
        System.out.println("Here is the Evens: ");
        System.out.println(evenCount);
        System.out.println("Here is the Odds");
        System.out.println(oddCount);
        return randomEight;


    }

    public static int[] sortArrayAndReturnSmallestLargest(int[] randomEight){
        int[] smallestLargest = new int[2];
        Arrays.sort(randomEight);
        smallestLargest[0] = randomEight[0];
        smallestLargest[1] = randomEight[7];
        return smallestLargest;
    }


}

我的输出:

Here is the Evens: 
53
Here is the Odds
11
Here is the Lowest number 
53
Here is the Largest number 
96
Here is the array
[53, 54, 57, 58, 62, 75, 80, 96]

示例输出:

 The lowest element is 59
 The highest element is 96
 Here is the array
 59 64 76 77 80 88 91 96 
 Evens: 5, odds: 3
 Total: 631

Answer 1

为了解决问题的第二部分，您可以这样做:

private int[] sortArrayAndReturnSmallestLargest(int[] randomArray){
    int[] smallestLargest = new int[2];
    Arrays.sort(randomArray);
    smallestLargest[0] = randomArray[0];
    smallestLargets[1] = randomArray[randomArray.size()-1];
    return smallestLargest
}

要从 main 方法中使用上述内容:

int[] smallestLargest = sortArrayAndReturnSmallestLargest(randomEight)

我不想为你完成全部作业。我的目的是向您展示如何做一些您还不舒服的事情。根据说明，您应该能够使用下面的循环来计算、求和和打印您需要执行的大部分操作。

为了获得偶数和奇数的计数，您需要创建计数器，循环 randomArray 并根据 int 值是偶数还是奇数递增每个计数器的计数。您可以执行如下操作:

int evenCount = 0;
int oddCount = 0;

for(int item: randomEight){
   //Use modulo to determine even vs odd
   if(item % 2 == 0){
       evenCount++;
   } else {
       oddCount++;
   }
}

这是完整的代码。我写的这是一个文本文件，所以我不 promise 任何事情。正如您所看到的，我接受了作业并将每个句子分解为评论，以便您可以了解需要如何看待这些事情。

import java.util.Arrays;
import java.util.Random;

public class Assignment1 {

public static void main(String[] args){

private static Random rand = new Random();
int evenCount = 0;
int oddCount = 0;
int sum = 0;

//Declare an array to hold eight integers. 
int[] arrayWithEightInts = new int[8];

//Use a for loop to add eight random integers, all in the range from 50 to 100, inclusive, to this array. Duplicates are okay.

for (int x = 0; x < 8; x++){
        arrayWithEightInts [x] = rand.nextInt((100 - 50) + 1) + 50;
}

//Next, pass the array to a method that sorts the array and returns another array containing only the largest and smallest elements in the original array. 
int[] smallestLargest = sortArrayAndReturnSmallestLargest(arrayWithEightInts);

//Print these two values in main. 
System.out.println(“The lowest element is ” + smallestLargest[0];
System.out.println(“The highest element is ” + smallestLargest[1];

//Then use a foreach loop to display all elements of the sorted array on one line separated by a single space. This latter loop should also count the odd and even numbers in the array and determine the sum of all elements in the array.
System.out.println(“Here is the array”);
for(int item: arrayWithEightInts){
    sum = sum + item;
    System.out.print(item + “ ”);
    if(x % 2 == 0){
                evenCount++;
    } else {
                oddCount++;
    }
}
System.out.println();
System.out.println(“Evens: ” + evenCount + “, odds: “ + oddCount);
System.out.println(“Total: ” + sum);
}


public static int[] sortArrayAndReturnSmallestLargest(int[] randomEight){
    int[] smallestLargest = new int[2];
    Arrays.sort(randomEight);
    smallestLargest[0] = randomEight[0];
    smallestLargest[1] = randomEight[randomEight.size()-1];
    return smallestLargest;
}
}