c++ - 使用临时变量 C++ 反转数组

Question

尝试使用临时变量反转数组中的元素。我不知道该怎么做

int arraysize = 12;//Size of the array
int option;// Option to be switched
int list[12];//numbers in the array
int total = 0;// Total of all numbers initialised to zero
double average = 0;// average of all numbers
int largestNum = 0;//largest Number
int smallestNum = 6;//first number in the array
int NumberOccurance = 0;// number of times the checked number appears
int usernum;//number to be check for times it appears
int userscaleup;//number to be multiplied by the array contents
int tempnum;// store the value
int endarray;
ifstream infile("data.dat");
ofstream outfile("output.dat");

do
{
    cout << "\t7. Reverse Order\n";

    cin >> option;// Taking in the users option from the menu

    switch (option)

    case 7:

    case 7:

        for (int index = 0; index < arraysize/2; index++, endarray--)
        {
            infile >> list[index];

            int endarray = list[arraysize];// variable endarray holds value of end side of array

            int swapholder = list[index];

            list[index] = list[endarray];//Swap 

            list[endarray] = swapholder;


            cout << list[index] << ' ';

        }
        break;

        while (option != 9);
}

我不断得到随机负数的输出。尝试了多种解决方案。我注释掉的行也给出了随机负数。

数组大小为 12。

必须使用临时变量来执行此操作。有人可以告诉我正确的方法吗？

编辑:更新了我的代码。该程序现在正在构建，但是当我运行它时它崩溃了。有什么建议吗？

Answer 1

尝试:

int temp = 0;
for (int index = 0, backwardsIndex = arraysize - 1; index < arraysize / 2; index++, backwardsIndex--)
{
    temp=list[index];
    list[index]=list[backwardsIndex];
    list[backwardsIndex]=temp;
}