linux - 如何从每个具有匹配文本的文件中删除行？

Question

$ grep "console.log" * -R
account/db.js:        console.log(err);
account/db.js:        console.log(info);
account/db.js:                console.log(err);
account/db.js:                    console.log(err2);
account/controller.js:    console.log(covers);
account/controller.js:    console.log(req.api_user);
account/controller.js:    console.log(code);
account/controller.js:        console.log(user);
account/helper.js:                console.log(err);
messages/db.js:        console.log("Error " + err);
messages/helper.js:                console.log('No email notify.');
messages/helper.js:                console.log(msg_body);
messages/helper.js:                        console.log(message.sid);
messages/helper.js:                        console.log(message.dateCreated);
messages/helper.js:                        console.log(error);
products/controller.js:            console.log(product);
products/controller.js:                console.log(product);
products/helper.js:        console.log(data)
products/helper.js:    console.log('removing index....');
profile/db.js:                console.log(err);
profile/db.js:                console.log(info);
profile/db.js:                console.log(err);
profile/controller.js:                            console.log("sending phone confirmation text...");
profile/helper.js:            console.log(message.sid);
profile/helper.js:            console.log(message.dateCreated);
profile/helper.js:            console.log(error);
receiver/controller.js:    console.log(from);
receiver/controller.js:    console.log(body);
receiver/controller.js:        console.log(from_email);
receiver/controller.js:        console.log(to_id_gen);
receiver/controller.js:        console.log(finalbody);
receiver/controller.js:                            console.log(result);
reviews/db.js:        console.log(err);
reviews/db.js:        console.log(results);
reviews/controller.js:            console.log(review);
reviews/controller.js:    console.log(review_id);
search/controller.js:        console.log(JSON.stringify(data.hits.hits, null, 4));

如您所见，在我编写代码时，我到处都在执行 console.log。

现在，我想删除所有这些行。我不想手动进入每个文件来删除它们。相反，我想通过命令来完成。

类似于grep "console.log"* -R，我如何做同样的事情但递归地删除那些行？ (从我的当前目录一直查看树下的每个文件)

Answer 1

尝试find 寻找这样的东西。试试 find 。 -type f -exec sed -i '/console\.log/d' {}\; 但您可能对使用 -i.bak 而不是 -i 感兴趣 保留备份副本