linux - 意外标记附近的语法错误 `fi' 自定义脚本

Question

我刚才测试时写了一个两部分的脚本，分别称为“bips.sh”和“chekdup.sh”，它显示:

bips.sh: line 17: syntax error near unexpected token `fi'
bips.sh: line 17: `fi'

这是脚本:

---bips.sh---
#!/bin/bash -x
# find broadcast ip's that reply with 30+ dupes.

# i decided to make this script into two sections. when running this make
# sure both parts are in the same directory.
if [ $# != 1 ]; then
echo "$0 <domain - ie: college.edu>"
else
host -l $1 | grep 'has address' | cut -d' ' -f4 > $1.ips
cat $1.ips | cut -d'.' -f1-3 | sort |\
awk '{ print echo ""$1".255" }' > $1.tmp
cat $1.tmp | uniq | awk '{ print "./chekdup.sh "$1"" }' > $1.ping
rm -f $1.ips $1.tmp
chmod 700 $1.ping
./$1.ping
rm $1.ping
fi

脚本的第二部分

---chekdup.sh---
#!/bin/bash -x
# this checks possible broadcast ip's for a given amount of icmp echo
# replies.
ping -c 2 $1 > $1.out
if
cat $1.out | grep dupl > /dev/null
then
export DUPES="`cat $1.out | grep dupl | cut -d'+' -f2 | cut -d' ' -f1`"
else
export DUPES=1
fi
if [ $DUPES -gt 30 ]; then
echo "$1 had $DUPES dupes" >> bips.results
rm -f $1.out
else
rm -f $1.out
fi

注意:我更新了代码，它总是报错

Answer 1

读那段代码太痛苦了，我不得不重写它

#!/bin/bash -x
# find broadcast ip's that reply with 30+ dupes.

if (( $# != 1 )); then
    echo "$0 <domain>"
    echo "example: $0 college.edu"
    exit
fi

host -l $1 |
awk '
    /has address/ {sub(/[0-9]+$/, "255", $NF); ips[$NF]}
    END {for (ip in ips) print ip}
' |
sort |
while read ip; do
    dupes=$( ping -c 2 $ip | grep -oP 'dupl.*\+\K\S+' )
    if [[ $dupes && $dupes -gt 30 ]]; then
        echo "$ip had $dupes dupes"
    fi
done >> bips.results