java - 是否可以在 Java 方法中声明扫描仪变量来读取键盘输入？

Question

final int MAX_ROUNDS = 5;
String name1,name1;

Scanner keyboard = new Scanner(System.in);
System.out.println("Please enter player1 name: ");
name1 = keyboard.nextLine();
System.out.println("Please enter player2 name: ");
name2 = keyboard.nextLine();
Player player1 = new Player(name1);
Player player2 = new Player(name2);

Dealer dealer = new Dealer();

    for(int count = 1; count <=MAX_ROUNDS; count++)
    {
        System.out.println("------------------");
        System.out.ptintf("Round : %d",count);
        dealer.rollDice();
        player1.makeGuess();
        player2.makeGuess();
        roundResults();

摘自属于 Player 类的 makeGuess 方法。

public void makeGuess()
{
Scanner keyboard = new Scanner(System.in)

System.out.printf("Please guess 'even' or 'odd' "+
        "%s.", name);
String answer = keyboard.nextLine();

        if(answer.equalsIgnoreCase("even")
            guess = "Cho (even)";
        else
            guess = "Han (odd);
  }

当该方法执行时，我没有收到任何提示，我无法理解为什么我没有包含该程序的所有内容。只是想知道是否有人关注此代码可以看到一些明显的东西，否则我将删除猜测提交。

Answer 1

虽然我找不到您的代码有任何问题，但如果我必须进行有根据的猜测，dealer.dice() 方法可能有一个无限循环，这会导致您的整个程序出现故障