python - Django:搜索相关模型

Question

您好，我想创建一个简单的搜索表单，以便从相关模型中获取数据。

我有 3 个模型:

class Person(models.Model):
    name = models.CharField()
    surname = models.CharField()

class Phone(models.Model):
    person = models.ForeignKey(Person,on_delete=models.CASCADE,related_name="phones")
    phone = models.CharField(0

class Email(models.Model):
    person = models.ForeignKey(Person,on_delete=models.CASCADE, related_name="emails")
    email = models.EmailField()

在我的主视图中我有:

def home(request):
    people = Person.objects.all()
    query = request.GET.get("q")
    if query:
        people = Person.objects.filter(Q(name__icontains=query)|Q(surname__icontains=query)|
                 Q(emails__contains=query)|Q(phones__icontains=query))
    //when I try emails_email__icontains=query I get error about no such fields

    return render(request,'app/home.html',{'users': people})

它工作正常，但我也想通过电子邮件和电话进行搜索(人们可以拥有很少的电子邮件和电话)。如果在我的查询中我使用另一个 OR (|)，我会收到错误消息，我无法在一个查询中组合 2 个模型。我也想尝试链:

people= above query
emails = Email.objects.filter(email__icontains=query)
context = chain(people,emails)

不幸的是，这个解决方案也行不通。我该如何解决这个问题？

编辑:模板

{% block content %}
   {%for user in users %}
      {{user.id }} {{user.name}} {{user.surname}}
      {% for email in user.email_set.all %}
         {{email}}
      {% endfor %}
    {% endfor %}

Answer 1

试试这个

在模型中

class Person(models.Model):
    name = models.CharField()
    surname = models.CharField()

class Phone(models.Model):
    person = models.ForeignKey(Person,on_delete=models.CASCADE, related_name='a')
    phone = models.CharField(0

class Email(models.Model):
    person = models.ForeignKey(Person,on_delete=models.CASCADE, related_name='b')
    email = models.EmailField()

在过滤器中

from django.db.models import Q

people = Person.objects.filter(Q(name__icontains=query)|Q(surname__icontains=query)|Q(b__email__icontains=query))

在模板中

{% block content %}
{% for user in users %}
    {{user.id }} {{user.name}} {{user.surname}}
    {% for email in user.b.all %}
       {{email.email}}
    {% endfor %}
{% endfor %}

希望对你有帮助