java - 如何通过镜头让玩家被摧毁？

Question

我在让玩家通过镜头被摧毁时遇到了一些麻烦。在我的应用程序中，我让相机跟随玩家(球)。但摄像机只能跟随球向上。所以我想要完成的是，当玩家(球)到达界面(屏幕)的底部时，它就会被摧毁。当它被摧毁后，如果弹出一个新的 Activity (新屏幕)，那就太好了，那就是“游戏结束”。非常感谢大家的大力支持。 the interface of the application

com.luca.tuninga 包；

import com.badlogic.gdx.ApplicationAdapter;
import com.badlogic.gdx.Gdx;
import com.badlogic.gdx.graphics.GL20;
import com.badlogic.gdx.graphics.Texture;
import com.badlogic.gdx.graphics.OrthographicCamera;
import com.badlogic.gdx.Input;
import com.badlogic.gdx.math.MathUtils;
import com.badlogic.gdx.math.Vector2;
import com.badlogic.gdx.physics.box2d.*;



public class MyGdxGame extends ApplicationAdapter {


public static float APP_FPS = 60f;
public static int V_WIDTH = 480;
public static int V_HEIGHT = 640;


Box2DDebugRenderer b2dr;
World world;
Body ballBody;

OrthographicCamera camera;

float cameraMaxY;

@Override
public void create() {
    world = new World(new Vector2(0, -9.8f), false);
    b2dr = new Box2DDebugRenderer();


    camera = new OrthographicCamera();
    camera.setToOrtho(false, V_WIDTH, V_HEIGHT);
    cameraMaxY = camera.position.y;


    ballBody = createBall();
    createWalls();
}

private void update() {
    world.step(1f / APP_FPS, 6, 2);

    if (Gdx.input.isTouched()) {
        ballBody.setLinearVelocity(0, MathUtils.clamp(ballBody.getLinearVelocity().y, 0, 3));
        ballBody.applyForceToCenter(new Vector2(0, 650f), false);
    }

    if (ballBody.getPosition().y * 32 > cameraMaxY) {
        camera.translate(0, (ballBody.getPosition().y * 32) - cameraMaxY);
        camera.update();

        cameraMaxY = camera.position.y;
    }
}

@Override
public void render() {
    Gdx.gl.glClearColor(.25f, .25f, .25f, 1);
    Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);

    update();

    b2dr.render(world, camera.combined.cpy().scl(32f));
}

@Override
public void dispose() {
    super.dispose();
    world.dispose();
}

private Body createBall() {
    Body body;
    BodyDef def = new BodyDef();
    def.type = BodyDef.BodyType.DynamicBody;
    def.fixedRotation = true;
    def.position.set(camera.position.x/ 32 + .5f, camera.position.y/ 32);
    def.gravityScale = 3;
    CircleShape shape = new CircleShape();
    shape.setRadius(.5f);

    body = world.createBody(def);
    body.createFixture(shape, 1.0f);
    return body;

}

private void createWalls() {
    Body body;
    BodyDef def = new BodyDef();
    def.type = BodyDef.BodyType.StaticBody;
    def.fixedRotation = true;

    PolygonShape shape = new PolygonShape();
    shape.setAsBox(1, 200 / 32);
    for(int i = 0; i < 20 ; i++) {
        def.position.set(1.01f, i * (200 / 32));
        body = world.createBody(def);
        body.createFixture(shape, 1.0f);

        def.position.set(V_WIDTH / 32 - 1, i * (200 / 32));
        body = world.createBody(def);
        body.createFixture(shape, 1.0f);
    }
 }

}

Answer 1

据我了解，相机只会向上跟随。因此，当球过渡到向上位置时，相机将更新并跟随，相机不会再次下降。

这样您就可以检查球何时在摄像机视线之外；特别是相机的底部。

您可以执行类似的操作，将其放在 update() 函数的末尾

if ((ballBody.getPosition().y + 0.5f) * 32 < ballBody.getPosition().y -
    camera.getViewportHeight()/2) {
    // destroy body
    world.destroyBody(ballBody);

    // TODO: switch to another screen (thus next frame update & draw loop of this screen won't be called anymore)
}

上面是检查球是否完全超出相机的视线(因此我使用+ 0.5f，这是您用来创建此类物体形状的半径)相对于相机的视口(viewport)高度。

然后切换到另一个屏幕。这意味着当前屏幕将不再更新或绘制其内容，因此不需要检查标志。 但是如果你需要在下一帧中再次执行其他操作，你最好在当前屏幕上有一个标志检查，以了解游戏现在已经结束，从而可以检查是否执行某些操作。