python - 遍历两个列表并更新其中一个的元素

Question

循环遍历两个大小相等的 pd.series 列表。如果 lst_1 中的系列元素全为零且 lst_2 中的相同索引元素为 None，如何更新 None lst_2 的元素与 lst_1 的元素在同一索引中？

# original lst_1 and lst_2
lst_1 = [pd.Series([1,0,1,0]), pd.Series([0,0,0,0]), pd.Series([2,0,2,0])]
lst_2 = [pd.Series([1,0,1,1]), None, pd.Series([2,2,0,0])]

# My try
for i, j in zip(lst_1, lst_2):
    if (i.all() == 0) and (j is None):
        j = pd.Series([0]*len(i))
        # have got this far...

预期结果:

lst_1 = [pd.Series([1,0,1,0]), pd.Series([0,0,0,0]), pd.Series([2,0,2,0])]
lst_2 = [pd.Series([1,0,1,1]), pd.Series([0,0,0,0]), pd.Series([2,2,0,0])]

Answer 1

这应该有帮助:

for i in range(len(lst_1)):
    if (lst_1[i].all() == 0) and lst_2[i] is None:
        lst_2[i] = lst_1[i]