python - 删除带有条件的列表中的字典

Question

我有下面的字典列表，我需要删除具有相同 received_on 和 customer_group 值的字典，但随机留下一个项目。

data = [
    {
        'id': '16e26a4a9f97fa4f',
        'received_on': '2019-11-01 11:05:51',
        'customer_group': 'Life-time Buyer'
    },
    {
        'id': '16db0dd4a42673e2',
        'received_on': '2019-10-09 14:12:29',
        'customer_group': 'Lead'
    },
    {
        'id': '16db0dd4199f5897',
        'received_on': '2019-10-09 14:12:29',
        'customer_group': 'Lead'
    }
]

预期输出:

[
    {
        'id': '16e26a4a9f97fa4f',
        'received_on': '2019-11-01 11:05:51',
        'customer_group': 'Life-time Buyer'
    },
    {
        'id': '16db0dd4199f5897',
        'received_on': '2019-10-09 14:12:29',
        'customer_group': 'Lead'

    }
]

Answer 1

这是获取第一个唯一日期时间的一种方法，如果你想要随机项目，你可以像 here 中那样先打乱列表。

data = [
    {
        'id': '16e26a4a9f97fa4f',
        'received_on': '2019-11-01 11:05:51',
        'customer_group': 'Life-time Buyer'
    },
    {
        'id': '16db0dd4a42673e2',
        'received_on': '2019-10-09 14:12:29',
        'customer_group': 'Lead'
    },
    {
        'id': '16db0dd4199f5897',
        'received_on': '2019-10-09 14:12:29',
        'customer_group': 'Lead'
    }
]

datetime = set()
result = []
for d in data:
    dt = d['received_on']
    if dt not in datetime:
        result.append(d)
        datetime.add(dt)
result

输出:

[{'id': '16e26a4a9f97fa4f',
  'received_on': '2019-11-01 11:05:51',
  'customer_group': 'Life-time Buyer'},
 {'id': '16db0dd4a42673e2',
  'received_on': '2019-10-09 14:12:29',
  'customer_group': 'Lead'}]