python - 使用循环命令创建多个字典变量？

Question

这是我第一次使用 python。我正在尝试为每个县(总共 23 个)创建一个字典，其中年份作为人口和收入值的关键。强力武装代码似乎可行，但我确信有一种更简单的方法可以使用循环或类来完成它......有什么建议吗？谢谢!!!!!!

import xlrd

wb= xlrd.open_workbook('C:\Python27\Forecast_test.xls')

popdata=wb.sheet_by_name(u'Sheet1')
incomedata=wb.sheet_by_name(u'Sheet2')

WyomingCnty =('Albany', 'Big Horn',
        'Campbell', 'Carbon', 'Converse',
        'Crook', 'Fremont', 'Goshen',
        'Hot Springs','Johnson', 'Laramie',
        'Lincoln', 'Natrona','Niobrara',
        'Park', 'Platte', 'Sheridan', 'Sublette',
        'Sweetwater', 'Teton', 'Uinta', 'Washakie', 'Weston','Wyoming')

Years = ('y0','y1','y2','y3','y4','y5','y6','y7','y8','y9','y10',
    'y11','y12', 'y13', 'y14', 'y15', 'y16', 'y17', 'y18','y19',
    'y20','y21','y22','y23','y24','y25','y26','y27','y28','y29','y30')

AlbanyPop = popdata.col_values(colx=1,start_rowx=1,end_rowx=None)
AlbanyIncome= incomedata.col_values(colx=1,start_rowx=1,end_rowx=None)
AlbanyDict1=dict(zip(Years,AlbanyPop))
AlbanyDict2=dict(zip(Years,AlbanyIncome))

BigHornPop = popdata.col_values(colx=2,start_rowx=1,end_rowx=None)
BigHornIncome= incomedata.col_values(colx=2,start_rowx=1,end_rowx=None)
BigHornDict1=dict(zip(Years,BigHornPop))
BigHornDict2=dict(zip(Years,BigHornIncome))

Answer 1

popdict = {}
incdict = {}
for ix, city in enumerate(WyomingCnty):
  popdict[city] = dict(zip(Years, popdata.col_values(colx=ix + 1,start_rowx=1,end_rowx=None)
  incdict[city] = dict(zip(Years, incomedata.col_values(colx=ix + 1,start_rowx=1,end_rowx=None)