结合范围和数字列表的python

Question

range(5, 15) [1, 1, 5, 6, 10, 10, 10, 11, 17, 28]
range(6, 24) [4, 10, 10, 10, 15, 16, 18, 20, 24, 30]
range(7, 41) [9, 18, 19, 23, 23, 26, 28, 40, 42, 44]
range(11, 49) [9, 23, 24, 27, 29, 31, 43, 44, 45, 45]
range(38, 50) [1, 40, 41, 42, 44, 48, 49, 49, 49, 50]

我从一个函数的打印命令中得到上面的输出。我真正想要的是范围的组合列表，例如顶行 5,6,7...15,1,1,5,6 等。输出范围来自

range_draws=range(int(lower),int(upper))

我天真地认为会给出一个范围。其他数字来自切片列表。

谁能帮我得到想要的结果。

Answer 1

range() 函数返回一个特殊的 range object节省内存(当只有开始、结束和步长大小时，不需要将所有数字保存在内存中)。将其转换为列表以“扩展”它:

list(yourrange) + otherlist

引用文档:

The advantage of the range type over a regular list or tuple is that a range object will always take the same (small) amount of memory, no matter the size of the range it represents (as it only stores the start, stop and step values, calculating individual items and subranges as needed).