python - Caesar Cipher Python - 附加功能

Question

所以目前，我的代码看起来像这样(感谢我在另一篇文章中的帮助)

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ("Encrypted text is: ")

for character in phrase: 
     #Loops through phrase and shows ascii numbers, example: hello is: 104,101,108,108,111
    x = ord(character)

     #adds a shift to each character so if shift is 1 'hello' becomes: ifmmp 105,102,109,109,112
    result += chr(x + shift)


print "\n",result,"\n"

问题是，如果我输入多个单词，例如:hello world，移位 1

输出是:ifmmp!xpsme

感叹号显示为空格(因类次而异)。我正在考虑做一个 if 语句来检测空格:

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ("Encrypted text is: ")

for character in phrase: 
        #Loops through phrase and shows ascii numbers, example: hello is: 104,101,108,108,111
    x = ord(character)

    if x == ord(' '):
        print "\nfound a space space"

        #adds 1 to each character so 'hello' becomes: ifmmp 105,102,109,109,112
    result += chr(x + shift)


print "\n",result,"\n"

但我不知道如何将空格添加到结果变量中。另外，我在这个线程中看到:Caesar's Cipher using python, could use a little help

JeffB 使用 while 循环来处理 ASCII 表 32 是空格，127 是 DEL。他为什么用96？我不明白。

while x < 32:
    x += 96

while x > 127:
    x -= 96

抱歉，这个问题太长了。提前谢谢了!您的帮助对我来说非常宝贵。

Answer 1

你可以直接跳过空格:

for character in phrase:
    x = ord(character)

    if character == ' ':
        result += ' '
    else:
        result += chr(x + shift)

您的类次不会将输出限制为仅 ASCII。如果你想确保这一点，你应该使用模运算符:

chr(32 + (x + shift) % (127 - 32))