java - 使用 mFusedLocationClient 获取 Firebase 服务中的当前位置

Question

我是 java/android 开发新手，所以我的代码可能很愚蠢。

我有一个使用 google map 的网站，网站上有一个按钮，可以使用 firebase 将推送 cURL 消息发送到特定设备。我希望设备能够获取当前位置并更新我的数据库。

我正在使用 MyFirebaseMessagingService 和 onMessageReceived 来获取 cURL 消息，一切正常，但当我开始进入位置代码时它会中断。我遇到了各种错误，因此我尝试创建一个类来获取位置，然后在我的服务中调用该类的方法。

类(class):

 public class LocationMedium {

private FusedLocationProviderClient mFusedLocationClient;
private Context mContext;

public LocationMedium(Context context) {
    mContext=context;
}


public void getLocation() 
{
    mFusedLocationClient = LocationServices.getFusedLocationProviderClient(mContext);

    if (ActivityCompat.checkSelfPermission(mContext, android.Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED && ActivityCompat.checkSelfPermission(mContext, android.Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED) {

        //currently pointless

        //return;
    }


    mFusedLocationClient.getLastLocation()
            .addOnSuccessListener((Activity)mContext, new OnSuccessListener<Location>() {
                @Override
                public void onSuccess(Location location) {
                    Log.d("mytag", "2222");
                    // Got last known location. In some rare situations this can be null.
                    if (location != null) {
                        // Logic to handle location object
                        double x = location.getLatitude();
                        double y = location.getLongitude();


                        Log.d("mytag1", String.valueOf(x));

                        Log.d("mytag2", String.valueOf(y));
                        String user = PreferenceManager.getDefaultSharedPreferences(mContext).getString("USERNAME", "none");
                        MyFirebaseInstanceIDService firebase = new MyFirebaseInstanceIDService();
                        firebase.onDeadline(user, x, y);


                    } else //no location found
                    {
                        String user = PreferenceManager.getDefaultSharedPreferences(mContext).getString("USERNAME", "none");
                        MyFirebaseInstanceIDService firebase = new MyFirebaseInstanceIDService();
                        firebase.onDeadline(user, 0, 0);
                        Log.d("mytag", "hmm");
                    }
                }
            });
    //END OF LOCATION

    Log.d("mytag", "theend");


}//end of run

}

我从 MyFirebaseMessagingService 中调用它

        if (Objects.equals(user, " location ")) {
        Handler handler = new Handler(Looper.getMainLooper());
        handler.post(new Runnable() {
            public void run() {
                LocationMedium task = new LocationMedium(context);
                 task.getLocation();
            }
        });
    }

我得到的错误是:

MyFirebaseMessagingService cannot be cast to android.app.Activity

它似乎在这一行:

mFusedLocationClient.getLastLocation()

我尝试从以下位置删除( Activity )位:

 .addOnSuccessListener((Activity) mContext, new OnSuccessListener<Location>() 

并将其更改为:

 .addOnSuccessListener(mContext, new OnSuccessListener<Location>()

但随后我收到错误:

Cannot resolve method 'addOnSuccessListener...'

也许我的处理方式完全错误。任何帮助/建议将不胜感激。谢谢。

Answer 1

.addOnSuccessListener(mContext, new OnSuccessListener<Location>()

用这个替换上面的代码，

.addOnSuccessListener(new OnSuccessListener<Location>()

为我工作。